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3 years ago

Which of these changes will increase the vapor pressure of water in a sealed container?

Chemistry

1 answer:

Vlad1618 [11]3 years ago

3 0

Answer:

Option B

Explanation:

Salt is a non-volatile solute and hence adding salt will increase the boiling point of water and hence reduce the vapor pressure. While on the other hand, adding more water will require more time to boil and hence produce vapor and thus the vapor pressure. Shaking will also not help in increasing the vapor pressure. Thus, only increasing the temperature of the water will create more vapors at a faster rate and hence increase the vapor pressure.

Thus, option B is the correct answer

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How many times higher is the concentration of H+ in the Hubbard Brook sample than in unpolluted rainwater?

Anna [14]

Answer:

1. 7 (a neutral solution)

Answer: 10-7= 0.0000001 moles per liter

2. 5.6 (unpolluted rainwater)

Answer: 10-5.6 = 0.0000025 moles per liter

3. 3.7 (first acid rain sample in North America)

Answer: 10-3.7 = 0.00020 moles per liter

The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.

Explanation:

8 0

3 years ago

1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

RSB [31]

Answer : The number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $N_2$ gas = $1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm$ (1 atm = 760 mmHg)

V = Volume of $N_2$ gas = 985 mL = 0.982 L (1 L = 1000 mL)

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $0.0^oC=273+0.0=273K$

Now put all the given values in above equation, we get:

$(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K$

$n=5.78\times 10^{-11}mol$

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains $6.022\times 10^{23}$ number of molecules.

As, 1 mole of $N_2$ gas contains $6.022\times 10^{23}$ number of molecules

So, $5.78\times 10^{-11}$ mole of $N_2$ gas contains $(5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13}$ number of molecules

Therefore, the number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

8 0

3 years ago

Write the empirical formula of at least four binary iconic compounds that could be formed from the following ions:

Nat2105 [25]

Explanation:

<h2><em>Explain</em></h2><h2><em>Explainexplain</em></h2><h2><em>Explainexplainexplain</em></h2><h2><em>Explainexplainexplainexplain</em></h2><h2><em>Explainexplainexplainexplainexplain</em></h2>

7 0

3 years ago

Please help I need to correct I don't understand it

victus00 [196]

Answer is d. in hetrogeneous you can separate things from each other

4 0

3 years ago

Sodium has______ Valence electrons and bismuth has ________ electrons

Triss [41]

Answer:

Sodium has 1 valence electron and bismuth has 83 electrons (5 valence electrons)

Explanation:

5 0

4 years ago