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Dovator [93]
2 years ago
6

An isotope undergoes radioactive decay by emitting radiation that has no mass. What other characteristic does the radiation have

?
a. some shielding required

b. positive or negative charge

c. low penetrating power

d. no charge
Chemistry
2 answers:
Advocard [28]2 years ago
7 0

Answer : Option D) No charge

Explanation : An isotope undergoes radioactive decay by emitting radiation that has no mass. The radiation will not have any charge as it does not has any mass it will not emit a radiative charge.

It is known that there are some unstable radioactive isotopes which has no mass and the radiation thus has no charge in it.

spayn [35]2 years ago
5 0

Answer : Option D No charge just did the test

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In today's experiment, Solutions A and B are prepared as follows.
hram777 [196]

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

<h3>D. 0.160</h3>
3 0
2 years ago
Calculate hydrochloric acid (umol)in 200 ul of a<br> 0.5173Msolution of acid?
strojnjashka [21]

<u>Answer:</u> The moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}

We are given:

Molarity of solution = 0.5173 M

Volume of solution = 200\mu L

Putting values in above equation, we get:

0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol

Hence, the moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

7 0
2 years ago
22. Radon has a half-life of 3.83 days. How long will it take a 225 g sample to decay to 14.06 g? (3pts.)
prohojiy [21]

Answer:

15.32 days

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 3.83 days

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Time (t) =.?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 225 g

Amount remaining (N) = 14.06 g

Number of half-lives (n) =?

N = N₀ / 2ⁿ

14.06 = 225 / 2ⁿ

Cross multiply

14.06 × 2ⁿ = 225

Divide both side by 14.06

2ⁿ = 225 / 14.06

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 3.83 days

Number of half-lives (n) = 4

Time (t) =.?

n = t / t½

4 = t / 3.83

Cross multiply

t = 4 × 3.83

t = 15.32 days

Therefore the time for 225 g sample of Radon to decay to 14.06 g is 15.32 days

8 0
2 years ago
PLZ HELP When subjected to heat and pressure, a chemical sedimentary rock can be changed into which rock type?
vlada-n [284]
A metamorphic rock.....
7 0
3 years ago
Read 2 more answers
A 10g vial must have 45ml of diluent added to it. it has a powder volume of 5ml. how many mgr will be in each ml of the final so
Semenov [28]

The solution has a concentration 20 mgr in each mL of the final solution.

To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as

M = m/V

where M is concentration, m is mass of solute, V is the total volume of solution.

From the text we know that :

m = 10g

vsolvent = 45mL

vsolute = 5 mL

find the total volume (V)

V = vsolvent + vsolute

V = 45 + 5

V = 50mL

Then, find the concentration

M = m/V

M = 10gr / 50 mL

M = 1000 mgr / 50mL

M = 20 mgr / mL

Hence, the solution has a concentration 20 mgr in each mL of the final solution.

Find more on concentration at: brainly.com/question/17206790

#SPJ4

6 0
1 year ago
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