Answer:
8.45 moles are produced
Explanation:
CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl
From the equation, we can see that for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts
these is because for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl
therefore we have every 1x8.45(8.45) mole of CaCl₂ and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl
8.45 moles are produced in the reaction
the answer is true becuase The force needed to overcome static friction is usually less than that needed to overcome ______ friction
For the answer to the question above,
The re<span>action of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is
Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s) </span>
Hey there!
The number of vacancies per unit volume => ( Nv = 2.3*10²⁵ m⁻³ )
Avogrado's number => ( NA = 6.022*10²³ atoms/mol )
Density of material ( p ) in g/m³ :
1 g/cm³ = 1000000 g/m³ so:
7.40 * ( 1000000 ) = 7.40*10⁶ g/m³
Atomic mass = 85.5 g/mol
* Calculate the number of atomic sites per unit volume :
N = NA * p / A
N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5
N = 4.45*10³⁰ / 85.5
N = 5.212*10²⁸ atoms/m³
Therefore:
Calculate the fraction of vacancies :
Fv = Nv / N
Fv = 2.3*10²⁵ / 5.212*10²⁸
FV = 4.441*10⁻⁴
Hope that helps!