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Alexandra [31]
3 years ago
14

In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water:

Chemistry
1 answer:
just olya [345]3 years ago
7 0

Answer:

94.56KJ

Explanation:

1.7 grams of CH4 contains 1.7/16 moles of CH4.

If 1 mole of CH4 give 890KJ

1.7/16 moles of CH4 gives 1.7/16*890 = 94.56KJ

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Wood has a density of 0.531 g/cm3. What is the volume of 44 grams of wood?
Sunny_sXe [5.5K]

Answer:

<h3>The answer is 82.86 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of wood = 44 g

density = 0.531 g/cm³

It's volume is

volume =  \frac{44}{0.531}  \\  = 82.86252354...

We have the final answer as

<h3>82.86 cm³</h3>

Hope this helps you

3 0
3 years ago
HELP IT IS DUE TOMORROW!!fill out the last column of the table . Do they use ionic or covalent bonding​
morpeh [17]

C = covalent

I = Ionic

(I'm lazy to an extent)

An ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals.

H2 = C

Cl2 = C

O2 = C

HCl = C

LiF = I

NaCl = I

NaF = I

MgF = I

NH3 = C

CH4 = C

CO2 = C

NaP = I

N2 = C

NF3 = C

6 0
3 years ago
Read 2 more answers
Using the following balanced chemical equation 8 H2 + S8à 8 H2S. Determine the mass of the product (molar mass = 34.08g/mol) if
Karolina [17]

Answer: 7.29 g of H_2S will be produced from the given masses of both reactants.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of} H_2}=\frac{1.35g}{2.01g/mol}=0.672moles

\text{Moles of} S_8=\frac{6.86g}{256.5g/mol}=0.0267moles

8H_2+S_8\rightarrow 8H_2S

According to stoichiometry :

1 mole of S_8 require = 8 moles of H_2

Thus 0.0267 moles of S_8 will require=\frac{8}{1}\times 0.0267=0.214moles  of H_2

Thus S_8 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

As 1 mole of S_8 give = 8 moles of H_2S

Thus 0.0267 moles of S_8 give =\frac{8}{1}\times 0.0267=0.214moles  of H_2S

Mass of H_2S=moles\times {\text {Molar mass}}=0.214moles\times 34.08g/mol=7.29g

Thus 7.29 g of H_2S will be produced from the given masses of both reactants.

5 0
3 years ago
What is the chemical formula for the compound formed between chromium(iii) and the sulfate ion?
djverab [1.8K]
The formula for chromium iii and sulfate ion is 2+3(1+4)= 2+(3x5)
8 0
4 years ago
In the following table, all the columns for the element beryllium are filled out correctly.
scoundrel [369]
That is false..........
6 0
4 years ago
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