Which of the following is referenced in the modern "periodic law"
1 answer:
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Answer:
1.274 moles
Explanation:
The equation for the reaction can be represented as follows:
⇄
+
K = 0.060
K =
Concentration of =
Concentration of =
Concentration of = 0.398 moles
If we construct an ICE table for the above equation; we have:
⇄
+
Initial 0.398 0 0
Change - x + x + x
Equilibrium (0.398 - x) x x
K =
K =
K =
0.060 =
0.06(0.398-x) = x²
0.02388 - 0.060x = x²
x² + 0.060x - 0.02388 = 0 (quadratic equation)
a = 1; b= 0.06; c= -0.02388
Using quadratic formula;
=
=
=
=
=
= or
= or
= 0.1274 or -0.1874
We go by the positive value which says:
[x] = 0.1274 M
number of moles = 0.1274 × 10.0
= 1.274 moles
∴ the number of moles of Cl₂ produced at equilibrium = 1.274 moles