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larisa [96]
3 years ago
8

Which of the following is referenced in the modern "periodic law"

Chemistry
1 answer:
katovenus [111]3 years ago
4 0
Atomic number is correct
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Based on these ideas, what are the pro's and con's for both Sexual Reproduction and Asexual reproduction?
Svetradugi [14.3K]
Asexual
Pro:
1. inexpensive to make offspring (usually make a lot at a time and not invest a lot of time in raising them).
2. Do not need a mate to reproduce.
3. Can rapidly expand a population
Con:
1. genetically identical- prone to extinction because once a parasite has evolved to attack a specific genotype, it can kill them all.
2. Lineages usually don't last longer than a couple thousand years

Sexual:
Pros:
1. Genetically unique- so more likely to create a "successful" offspring
2. Lineages more likely to last hundreds of thousands of years

Cons:
1. More effort into creating offspring- require more parental effort
2. STD's- easily to pass
3. need to find a mate or else won't be successful as an organism.

Hope this helps you.
6 0
3 years ago
How will freezing the juice affect its mass?
expeople1 [14]

Answer:

Mass increases since its going from liquid to solid.

Explanation:

8 0
3 years ago
determine the frequency and wavelength (in nm) of the light emitted when the e- fell from n=4 and n=2
Lostsunrise [7]

Answer:

Frequency = 6.16 ×10¹⁴ Hz

λ = 4.87×10² nm

Explanation:

In case of hydrogen atom energy associated with nth state is,

En =  -13.6/n²

For n = 2

E₂ = -13.6 / 2²

E₂ = -13.6/4

E₂ = -3.4 ev

Kinetic energy of electron = -E₂ = 3.4 ev

For n = 4

E₄ = -13.6 / 4²

E₄ = -13.6/16

E₄ = -0.85 ev

Kinetic energy of electron = -E₄ = 0.85 ev

Wavelength of radiation emitted:

E = hc/λ = E₄ - E₂

hc/λ = E₄ - E₂

by putting values,

6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.85ev   - (-3.4ev )

6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 2.55 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s  /2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 2.55× 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 4.08×10⁻¹⁹ J

λ = 4.87×10⁻⁷ m

m to nm:

4.87×10⁻⁷ m ×10⁹nm/1 m

4.87×10² nm

Frequency:

Frequency = speed of electron / wavelength

by putting values,

Frequency = 3×10⁸m/s /4.87×10⁻⁷ m

Frequency = 6.16 ×10¹⁴ s⁻¹

s⁻¹ = Hz

Frequency = 6.16 ×10¹⁴ Hz

3 0
3 years ago
C + 2H2 -> CH4
ankoles [38]

Answer:

<u>C) 4</u>

Explanation:

<u>The reaction</u> :

  • C (s) + 2H₂ (g) ⇒ CH₄ (g)

       12g      4g             16g

Hence, based on this we can say that : <u>2 moles of hydrogen gas are needed to produce 16g of methane.</u>

<u />

<u>For 32g of methane</u>

  • Number of moles of H₂ = 32/16 × 2
  • Number of moles of H₂ = <u>4</u>
4 0
2 years ago
Read 2 more answers
A sample of argon gas has a volume of 698.7l. The temp is decreased to 24.8c and the volume also decreases to 499.1l. What was t
Rina8888 [55]
ASsfh 977. Hoon mein
4 0
3 years ago
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