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2 years ago

You have a 5-liter container with 1.30×10^24 molecules of ammonia gas (NH3) at STP.

Chemistry

2 answers:

Luden [163]2 years ago

7 0

<u>Answer:</u> The number of molecules of argon gas are $1.30\times 10^{24}$

<u>Explanation:</u>

We are given:

Volume of container = 5 L

Number of molecules of ammonia gas = $1.30\times 10^{24}$

STP conditions:

The temperature and pressure conditions are 273 K and 1 atm

Also, 1 mole of a gas occupies 22.4 L of gas

As, the conditions of same for argon gas. So, the number of molecules of argon gas will be equal to the number of molecules of ammonia gas.

Hence, the number of molecules of argon gas are $1.30\times 10^{24}$

givi [52]2 years ago

3 0

Answer:answer is C

Explanation:

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2 years ago

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3 years ago

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Evaluate the Lewis structures below and pick the statements that best describes the accuracy of each of the structures. There ma

Artyom0805 [142]

Answer:

The structures shown by dots and lines to give the exact number of electrons in the outer most shell is explained by Lewis Structures.

Explanation:

Lewis structures are those structures in which the diagram is shown using the electron representation. They are easy to understand as the diagram completely depicts where the electrons are shared and where they are transferred. The diagram also explains where there is a single bond and where there is a di covalent bond or tri covalent bond explaining where the single , double or triple electron pair is shared. The electrons are shown by dots or lines.

For example CCl₄ can be shown as follows

.. Cl..

.. ..

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.. Cl..

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Similarly methane CH4 can also be shown.

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3 years ago

Nitric oxide, NO, is made from the oxidation of NH3, and the reaction is represented by the equation: 4NH3 + 5O2 → 4NO + 6H2O Wh

tamaranim1 [39]

Answer:

16.16g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4NH3 + 5O2 → 4NO + 6H2O

Next, we shall determine the mass of NH3 and O2 that reacted from the balanced equation. This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g.

From the balanced equation above,

68g of NH3 reacted with 160g of O2.

Now, we can calculate the mass of O2 that will be required to react completely with 6.87 g of NH3. This is illustrated below:

From the balanced equation above,

68g of NH3 reacted with 160g of O2

Therefore, 6.87g of NH3 will react with = (6.87 x 160)/68 = 16.16g of O2.

Therefore, 16.16g of O2 is needed for the reaction.

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3 years ago