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Ghella [55]
3 years ago
8

The voltage of a battery can be changed by altering the _____

Chemistry
1 answer:
Eddi Din [679]3 years ago
8 0

the amperage or the resistance

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Flame tests are used to identify
sergij07 [2.7K]

Answer:

Explanation: The flame test is used to visually determine the identity of an unknown metal or metalloid ion based on the characteristic color.

Hope this helps

4 0
3 years ago
Read 2 more answers
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH}  =0.1900gO

4. Compute the moles of oxygen by using its molar mass:

n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1

6. Search for the closest whole number (in this case multiply by 2):

C_3H_6O_2

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

M=12*3+1*6+16*2=74g/mol

Which is about three times in the molecular formula, for that reason, the actual formula is:

C_9H_{18}O_6

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0
3 years ago
Why do things dissolve so well in water ?
Goshia [24]

Answer:

Explanation:

Water is called the universal solvent. It is a polar molecule (105 degree angle between the H atoms)   that gives it a + and a - side so to speak....which allows it to 'pull apart'  substances....overcome their intra-molecular attractions to each other ...i.e. disssovle them

4 0
3 years ago
What is the term used to describe a change in motion?
Irina-Kira [14]

Answer:

it should be momentum if im not mistaken

8 0
3 years ago
CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.23-L flask at a certain temperature initially contains 27.2 g CO and 2.36 g H2.
irga5000 [103]

Answer: 5.70M

Explanation:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.05 g/mol.

To determine the amount of each compound in the reaction mixture we use the formula.

Amount in mol = reacting mass/molar mass.

Inputing the given values we have,

26.6 g CO x (1 mol / 28.01 g ) = 0.9496608354 mol of CO.

To calculate the concentration of CO we use C=n/v, where n=amount and v= volume of CO.

Inputing the values in the formula

[CO] = 0.9496608354 mol CO / 5.23 L = 0.18158 M CO

Repeating thesame procedure for H

Amount of H=2.36 g H2 x ( 1 mol / 2.02 g ) = 1.168316832 mol of H2

Concentration of H2 in the mixture

[H2] = 1.168316832 mol H2 / 5.23 L = 0.223388 M of H2

Amount of CH3OH is determine similarly using rmass/molar mass

8.66 CH3OH x (1 mol / 32.05 g ) = 0.2702028081 mol of CH3OH

Concentration of

[CH3OH] = 0.2702028081 mol CH3OH/ 5.23 L = 0.051664 M CH3OH

Now equilibrium constant is determined by

Kc = [CH3OH] / [CO] [H2]^2

=0.051664/0.18158×0.223388×0.223388.

=5.70

7 0
3 years ago
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