65.2 g x (1 mol/163.9 g) = 0.398 moles of Na3PO4.
Answer:
Option A = 2.2 L
Explanation:
Given data:
volume of one mole of gas = 22.4 L
Volume of 0.1 mole of gas at same condition = ?
Solution:
It is known that one mole of gas at STP occupy 22.4 L volume. The standard temperature is 273.15 K and standard pressure is 1 atm.
For 0.1 mole of methane.
0.1/1 × 22.4 = 2.24 L
0.1 mole of methane occupy 2.24 L volume.
Answer is 3
s -1
p - 3
d - 5
f - 7
Answer:
To decrease the algae
Explanation:
Acid lakes have more algae than other lakes
