Which of the following illustrates the truth value of the given conditional statement? p: 2 + 2 = 4 q: 7 + 1 = 7 T F → F T T → T
F T → T F F → T
1 answer:
Answer:
T F → F is the correct answer.
Step-by-step explanation:
In the given question if p illustrates p: 2 + 2 = 4
which is true so the truth value of this statement p is True.
Now the other statement q illustrates q: 7 + 1 = 7
Which is a false statement so the truth value of this statement is False.
As we know when "p→q ( p implication q), the truth value of implication is False only when truth value of p is True and for statement q the truth value is False."
We can see from the truth table truth value of p→q will be False.
So T F → F
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The correct answer is A.
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A side note: Actually, option C has a constant of proportionality of two as well, except the roles of x and y are interchanged. I chose option A because usually you want the y = mx form, but the names of the variables are obviously meaningless.
We are given the following equation and want to find the possible values of x
Subtract both sides by 3x
Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.
In other words, there is no value of x that makes the equation true.
Let me know if you need any clarifications, thanks!
~ Padoru