Answer:
The mass of the block, M =T/(3a +g) Kg
Explanation:
Given,
The upward acceleration of the block a = 3a
The constant force acting on the block, F₀ = Ma = 3Ma
The mass of the block, M = ?
In an Atwood's machine, the upward force of the block is given by the relation
Ma = T - Mg
M x 3a = T - Ma
3Ma + Mg = T
M = T/(3a +g) Kg
Where 'T' is the tension of the string.
Hence, the mass of the block in Atwood's machine is, M = T/(3a +g) Kg
Explanation:
a) I = V / R
1.70 = 115 / R
R = 115 / 1.70
R = 67.647
R = 67.65 ohms
Therefore, equivalent resistance is 67.65 ohms
b) Equivalent resistance of circuit from above sum is 67.65 ohms
Given resistance of each bulb is 1.50 ohms
Number bulbs = Equivalent resistance / Resistance of each bulb
= 67.65 / 1.50
= 45
The change in momentum of the car is 45,000 kg m/s
Explanation:
The change in momentum of an object is given by:
where
m is the mass of the object
u is its initial velocity
v is its final velocity
For the car in this problem, we have
m = 900 kg
u = 30 m/s
v = 80 m/s
Therefore, the change in momentum is:
Learn more about momentum:
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Grade 3 is a completely torn ligament
