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4 years ago

How does approaching a temperature of absolute zero affect kinetic energy.?

Physics

1 answer:

Alexus [3.1K]4 years ago

7 0

First of all the kinetic energy is when the particles move in continuous random motion.

If the temperature is high the colliding particles will collide more. and if the temperature is low the colliding particles will collide less.

Low temperature result in low kinetic energy
High temperature result in high kinetic energy

Absolute zero is the point where where all molecules have no kinetic energy. It is a theoretical value (it has never been reached).

The Kelvin temperature scale is based on absolute zero being the lowest possible temperature that could theoretically be reached. That is why there is no such thing as a negative Kelvin temperature value.

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3 years ago

The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the 10-g bullet is traveling at 300 m/s

Nadusha1986 [10]

Answer:

$d=6.874mm$

Explanation:

Linear momentum of the block is conserved in the $x\prime$ direction since the impulsive force due to impact cancels each other internally.

$m_bv_b_x=(m_b+m_B)v_x\\(0.01)(300cos 30\textdegree)=(10+0.01)v\\\therefore v=0.259548m/s$

Using the conservation of energy to the block system considering the initial position:

$T_1+V_1=T_2+V_2\\\\0+0.5(m_b+m_B)v^2=0+(m_b+m_B)gh\\0.5(10+0.01)(0.259548)^2=(0.01+10)(9.8)\\h=0.003437m\\\therefore h=3.437mm$

Applying Sine rule:

$d=\frac{h}{Sin 30\textdegree}\\d=6.874mm$

Hence, the distance the block will slide up is 6.874mm

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3 years ago

Part of the earth that goes around the core and is solid

Olegator [25]

Answer:

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3 years ago

Read 2 more answers

A characteristic necessary to give a physical object movement?

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3 years ago

A sealed container holds 0.020 moles of ideal nitrogen (n2) gas, at a pressure of 1.5 atmospheres and a temperature of 290k. the

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Translational kinetic energy is the kinetic energy of an object of finite size. It is equal to one half the product of the mass of the object and the square of the velocity. For an ideal gas, it is simplified into the expression:

Kinetic energy = 3nRT / 2 where n is the number of moles, R is the universal gas constant and T is the temperature of the gas.

We calculate as follows:
Kinetic energy = 3nRT / 2
Kinetic energy = 3 (0.020 moles ) (8.314 J / mol-K) (290 K) / 2
Kinetic energy = 72.33 J

Therefore, the translational kinetic energy of the ideal nitrogen gas is 72.33 J.

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3 years ago