The velocity of the pitcher is <u>0.105 m/s</u> in a direction opposite to the velocity of the ball.
When no external force acts on a system, the total momentum of the system is conserved. The total initial momentum of the system is equal to the total final momentum of the system.
The pitcher and the ball are initially at rest, therefore, the total initial momentum of the system is zero.
Since no external forces act on the system comprising of pitcher and the ball, the total final momentum of the system is also equal to zero.
If the mass of the pitcher is mp and its speed is vp, the mass of the ball is mb and the ball's speed is vb, then the final momentum of the system of pitcher and the ball is given by,

Therefore,

Substituet 0.15 kg for mb, 50 kg for mp and 35 m/s for vb.

The pitcher has a velocity <u> 0.105 m/s</u> opposite to the direction of the velocity of the ball.
Given that the mass of the toy cart is 2.0 kg and and the acceleration is unknown, the normal formula would be a=f/m where a is acceleration, f is force and m is mass but the string's breaking strength is 40n so I think the formula in this case will be f is greater than m*a
40 is greater than 2a
40 is greater than 2a
40/2 is greater than 2a/2
20m/s² is greater than a
Therefore the maximum speed the toy cart should have should be less than 20m/s²
Your answer is
<span>126000</span>
Answer:
a)
b) 
Explanation:
a) The displacement of the first object is 22.5 m, so we can use the next equation:



positive acceleration.
b) Using the same equation we can find the second value of the acceleration:


positive acceleration.
I hope it helps you!