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3 years ago

Balanced forces can change an object's direction. A. True B. False

Physics

1 answer:

makvit [3.9K]3 years ago

8 0

Answer:

False

Explanation:

Balanced forces result in a net force of 0N. This means no direction or acceleration change will be applied to the object. A torque may be applied, but with no other external forces, the object will not move.

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Which of the following is located in the temperature climate zone?

barxatty [35]

The correct answer is C. Taiga hope it helps ( :

5 0

4 years ago

You are given a vector in the xy plane that has a magnitude of 90.0 units and a y component of -61.0 units. A) Assuming the x co

kvasek [131]

Answer:

A) magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

B)22.5° (clockwise form -ve X axis)

Explanation:

given vector = V1 = x i - 60 j

magnitude of V1 = 90

x - component can be found out by resultant formula

90^2 = x^2 + (-60)^2

x = 67.08 = 67.1 units (3sf)

FOR THE VECTOR 80 UNITS IN -VE X DIRECTION

The X component is -80-------(1)

The Y component is 0 ---------(2)

For the x- component of new added vector:

(1)----------- x + 67.1 = -80

x = -147.1 = -147.1

For the y- component of new added vector:

(2)---------- y - 61 = 0

y = 61.0 (3sf)

the new added vector is = -147.1 i + 61 j

magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

direction = arctan (61 / 147.1)

= 22.5° (clockwise form -ve X axis)

4 0

3 years ago

BRAINLEST FOR CORRECT ANSWER

xxMikexx [17]

Answer:

3kg sledgehammer swung at 1.5 m/s

Explanation:

Small Sledgehammer:

Mass:3.0

Velocity:1.5

MASS×VELOCITY=MOMENTUM

3.0×1.5= 4.5 (momentum)

Large Sledgehammer:

Mass:4.0

Velocity:0.9

4.0×0.9=3.6 (momentum)

higher momentum is the smaller Sledgehammer.

3 0

3 years ago

What is the wavelength of a wave that has a speed of 350 meters/second and a frequency of 140 hertz?In meters

Leto [7]

Apply:
wavelength = speed/frequency
= 350 m/s : 140 Hz = 2.5 m.

3 0

3 years ago

Read 2 more answers

A car of mass 487 kg travels around a flat, circular race track of radius 53.3 m. The coefficient of static friction between the

aleksklad [387]

Answer:

9.96 m/s

Explanation:

mass of car, m = 487 kg

radius of track, R = 53.3 m

coefficient of static friction, μ = 0.19

acceleration due to gravity, g = 9.8 m/s^2

let v be the maximum speed so that the car can go without flying off the track.

The formula for the maximum speed is given by

$v_{max}=\sqrt{\mu Rg}$

$v_{max}=\sqrt{0.19\times53.3\times9.8$

vmax = 9.96 m/s

8 0

3 years ago