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2 years ago

What is the relationship between amplitude and frequency of a wave?.

Physics

1 answer:

kondaur [170]2 years ago

5 0

Answer:

The relationship between the wave's amplitude and frequency is such that it is inversely proportional to the frequency. The amplitude decreases as the frequency increases. The amplitude increases as the frequency decreases. The higher the energy of a wave, the higher the amplitude. The lower the energy, the lower the amplitude. Energy has no effect on wavelength, speed, or frequency, only the amplitude.

Explanation:

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Product of my research: 1 HP = 746 watts .

12 HP = (12 x 746 W) = 8,952 W

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3 years ago

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Select which geologic events will have an immediate impact on the landscape. Choose three (3).

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Answer: A, B, and D,

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2 years ago

The unit of current, the ampere, is defined in terms of the force between currents. Two 1.0-meter-long sections of very long wir

Paha777 [63]

Answer:

1.6 x $10^{-7}$ N

Explanation:

If the force between two actual wires has this value, the current is defined to be exactly 1 A.

The force between two parallel wires carrying current can be defined as,

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where,

current $I_{1}$ = 1Amp

current $I_{2}$ = 2amp

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3 years ago

In the year 2000, a company made $4.7 million in profit. For each consecutive year after that, their profit increased by 15%. Ho

olya-2409 [2.1K]

Answer: $8.2 million.

Explanation:

If we have a quantity A, and we have an increase of x%, this can be written as:

A + (x%/100%)*A

Now, for this particular case we have:

In year 2000 (we can define this year as the year zero, y = 0) the initial value is $4.7 million.

The next year, y = 1, there is an increase of 15%, then we will have a profit of:

P = $4.7 million + (15%/100%)*$4.7 million = $4.7 million + 0.15*$4.7 million

P = $4.7 million*(1 + 0.15) = $4.7 million*(1.15)

in the next year, y = 2, the profit will be:

P = $4.7 million*(1.15) + (15%/100%)* $4.7 million*(1.15)

= $4.7 million*(1.15) + 0.15* $4.7 million*(1.15)

= $4.7 million*(1.15)^2

We already can see the pattern, the profit in the year y will be:

P(y) = $4.7 million*(1.15)^y

In particular, in the year 2004 we have y = 4, then the profit that year will be:

P(4) = $4.7 million*(1.15)^4 = $8.2 million.

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