Answer:
• The amount of heat required to melt ice and raise the temperature of water T^oCToC is
Q=mL_f+mc\Delta TQ=mLf+mcΔT
Here m=1.5 kgm=1.5kg
L_f=3.33*10^5 J/kgLf=3.33∗105J/kg is Latent heat of fusion of ice.
c=4186 J/kg.^oCc=4186J/kg.oC is heat capacity of water.
\Delta T=50 ^oC-0^oC=50^oCΔT=50oC−0oC=50oC
So,
Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 JQ=(1.50)[3.33∗105+(4186)(50)]=8.13∗105J
because of conduction the metal spoon is a conductor so the heat is getting traveled through the spoon and into your hand
1. that's 2 joules 1*2 = 2 j
2.that will be 20*3.5 = 70 j
3.that will be = 500*2.2= 1100 j
Answer:
option A: the government paid private industries for goods and services.
Explanation: