The correct answer is decreases
The further away you are the weaker it would be. That's why at one point you stop being in the field and ti doesn't pull you towards it anymore. Proportionally, if you move towards the Earth then it increases.
It is a false statement i.e. drift velocity is not same in the direction as the applied force.
Drift velocity of a current-carrying conductor can be explained as, the charges i.e. electrons do not flow in the same direction of current. In other word, in most cases the movement of the electrons is almost random, with a small net velocity. So that , the drift velocity, in the direction opposite to the electric field.
Drift velocity
is inversely proportional to the number of electron per unit volume of the conductor e. Therefore, the formulation can be given as ,
= σ E/ne
The above equation shows the drift velocity in a current carrying conductor
where,
is drift velocity , σ is the conductivity, E is electric force and n is number of electrons per unit volume of the conductor e.
Hence here we can say that, the drift velocity is not in the same direction as the applied force.
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Ignoring air resistance . . .
After the bomb is released, tangential (horizontal) acceleration is zero,, normal (vertical) acceleration is 9.8 m/s^2 down (gravity).
Answer:
this picture might help you
Explanation:
if you think correct pls mark brainliest
the missing force is spring force.
The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position. due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.
the spring force is given as
F = kx
where F = spring force ,k = spring constant , x = stretch in the spring.
the spring force balances the weight of the object in down direction and hence keeps the block from falling down.