Answer:
B) Both stirring and heating increase the rate of dissolving.
Explanation:
When we dissolve a solute in a solvent, it is separated into its constituting ions.
For example, if we dissolve salt in water, The NaCl is disassociated into its ions and
because of the interaction of
and
ions present in water.
if we can increase the amount of salt interacting with water, we can increase the rate of dissolving.
The picture below will provide a better understanding about the area of reaction.
In the figure a, salt is accumulated at the bottom, in this case only the salt molecules at the upper surface will be able to react with water.
In the figure b, salt grains are moving around the container. This increases the number of molecules interacting with water. This leads to quicker dissolving.
We can make the salt grains move by either heating or by stirring. So both stirring and heating will increase the rate of dissolving
Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
Hence, this is the required solution.
Answer:
<em>The velocity of the carts after the event is 1 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
In a system of two masses, the equation simplifies to:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
The m1=2 kg cart is moving to the right at v1=5 m/s. It collides with an m2= 8 kg cart at rest (v2=0). Knowing they stick together after the collision, the common speed is:
The velocity of the carts after the event is 1 m/s