3 years ago

Please help I will reward brainly

1 answer:

3 0

The answer is A, lunar.

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dalvyx [7]

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Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $1\times 10^{-2}mol/L.s$

t = time taken = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

$[A]_o$ = Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

$1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)$

$t=277.8s$

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

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3 years ago

Vinvika [58]

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Zepler [3.9K]

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bixtya [17]

Answer:3.5

Explanation:

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3 years ago