1 N₂ + 3 H₂ = 2 NH₃
Mole ratio <span> of hydrogen to ammonia :
3 moles H</span>₂ : 2 moles NH₃ or 3 : 2
hope this helps!
Answer:
From the mole ratio of the gases, 10 moles of hydrogen will produce 10 moles of water, and if 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
What is the mole ratio of reactants in the formation of water?
The mole ratio of the reactants in the formation of water can be shown from the equation below:
Mole ratio of hydrogen to oxygen is 2:1
10 moles of hydrogen will require 5 moles of oxygen, therefore hydrogen is the limiting reactant.
10 moles of hydrogen will produce 10 moles of water.
1 mole of a gas has a volume of 22.4 L.
If 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
Therefore, the volume ratio of gas equals mole ratio of gas
Explanation:
The answer to your question is electron
Answer:
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
is the constant of a certain reaction at equilibrium for gaseous reactants and products.
For the given chemical reaction:
The expression of for above equation follows:
As solids do not exert pressure, and are not involved.