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Finger [1]
3 years ago
7

2. Două surse coerente oscileaza cu frecventa de 1 Hz, iar undele generate de elel se propaga pe suprafața apei cu viteza de 1,

5 m/s . Determinați pentru ce valoare minima a diferenței de drum pe suprafața apei se va observa :a) amplitudinea undelor b) atenuarea undelor
Physics
1 answer:
hammer [34]3 years ago
3 0

Answer:

the correct answer is B

Explanation:

Attenuation We can define the attenuation of a wave as the decrease in its intensity as it moves away from the focus. It is exclusively due to the distribution of its energy over a growing surface. This happens in the aqueous environment or in the water when a wave dissipates.

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A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant
nika2105 [10]

Answer:

11.78meters

Explanation:

Given data

Mass m = 100kg

Length of cord= 10m

Spring constant k= 35N/m

At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy

That is

Us=Ug

Us= 1/2kx^2

Ug= mgh

1/2kx^2= mgh

0.5*35*10^2= 100*9.81*h

0.5*35*100=981h

1750=981h

h= 1750/981

h= 1.78

Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge

6 0
3 years ago
Read 2 more answers
What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

take care

8 0
3 years ago
Which element would you expect to gain one electron in a chemical reaction ?
Annette [7]

Answer: Hydrogen

Explanation: Which element would you expect to gain one electron in a chemical reaction ? HYDROGEN

Non-metals are more likely to gain electrons!

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

4 0
2 years ago
A student runs 35 m east, then 12 m west. What is the distance run by the student?
lora16 [44]
47m total just add them up 35 + 12 = 47
4 0
3 years ago
Read 2 more answers
A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca
love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. s_{o} = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

v_{i} = 33.2 m/s, a = 0 (since the velocity is constant), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

s = 33.2t .......... eq (1)

Hatchback:

a=5m/s^{2}, v_{i} = 0 m/s (since initial velocity is zero), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

putting in the data we will get

s=(1/2)(5)t^{2}

now putting 's' value from eq (1)

2.5t^{2}-33.2t=0

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

7 0
3 years ago
Read 2 more answers
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