Answer: 44.57°C
Explanation:
The following can be deduced from the question:
Specific heat of water = 4.186 J/kg
From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.
We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:
= 7.96 × 10⁴ /(625 × 4.186)
= 79600/(625 x 4.186)
= 79600/2616.25
= 30.43°C
The final temperature will then be:
= 75.0°C - 30.43°C
= 44.57°C
The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.
The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.

The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.
Learn more: brainly.com/question/13447525