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Luda [366]
3 years ago
10

What is the acceleration of a 1000 kg car subject to a 550 N net force

Physics
1 answer:
Xelga [282]3 years ago
4 0

Answer:

The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2

Explanation:

Given:

F = 550 N

m = 1000 kg

To Find:

a = ?

Solution:

So by the equation by Newton's 2nd Law of Motion,

F = m x a

550 N = 1000 kg x a

a = 550 N/ 1000 kg

a = 0.55 m/s^2

Therefore,

The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2

PLEASE MARK ME AS BRAINLIEST!!!

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3 years ago
Two billiard balls, each with a mass of 0.17 kg, collide with each other on a
Anastasy [175]

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Explanation:

7 0
3 years ago
What is the formula for Impedance for circuit with R, C, and L?
NikAS [45]

Answer:

 The formula for Impedance for circuit with R, C, and L are:

    z=\sqrt{R^{2}+\left ( \omega L-\frac{1}{\omega C} \right )^2}

The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.

3 0
3 years ago
How much thermal energy does it take to raise the temperature of 3.5 kg of water from 25°C to 46°C? The specific heat of water i
Alex_Xolod [135]

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6 0
3 years ago
Read 2 more answers
A 10- kilogram block is pushed across a horizontal surface with a horizontal force of 20 N against a friction force of 10 N. The
Temka [501]

Answer:

1m/s^2

Explanation:

Mass of block=10 kg

Applied horizontal force =F=20 N

Friction force=f=10 N

We have to find the acceleration of block.

Net force=Applied horizontal force-friction force

ma=F-f

Where F= Horizontal force

f=Friction force

m=Mass of object

a=Acceleration of object

10a=20-10=10

a=\frac{10}{10}=1 m/s^2

Hence, the acceleration of the block=1m/s^2

4 0
3 years ago
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