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Elina [12.6K]
3 years ago
13

Q. The probability that a student passes a statistics test is 2/3 and the

Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0

Answer:

4/9 or 44.44%

Step-by-step explanation:

We have the following probabilities:

Probability of winning the statistical test = P (s) = 2/3

Probability of winning the mathematics and statistics test = P (s n m) = 14/45

Probability of winning at least one test = P (s u m) = 4/5

We have that, the probability of winning the mathematics test P (m) can be found in the following way:

P (s n m) = P (s) + P (m) - P (s u m)

replacing we have:

14/45 = 2/3 + P (m) - 4/5

P (m) = 14/45 - 2/3 + 4/5

p (m) = 4/9 = 0.444

Which is the same as there is a 44.44% probability that I will win the math test

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Bezzdna [24]
The root \sqrt{10} can be converted into the power 10^{ \frac{1}{2} }. Therefore we can rewrite the problem as (10^{ \frac{1}{2} } )^ {\frac{3}{4} x} and then follow the exponent rules about a power to a power, multiplying 1/2 and 3/4 together.

Thus the problem becomes 10^{\frac{3}{8}x}, which then can be turned into \sqrt[8]{10} ^{3x}, making the last option our answer.

4 0
3 years ago
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
Can anyone help me ?
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3 years ago
Giving brainiest explain answer
enot [183]

Answer:

A.) -5

Step-by-step explanation:

<em>Slope Formula --->     </em>m = \frac{y_2 - y_1}{x_2 - x_1}       <em>m = slope</em>

m = \frac{2 - (-3)}{-2 - (-1)}

<em>Eliminate negatives:</em>

m = \frac{2 + 3}{ -2 + 1}

<em>Solve:</em>

m = \frac{5}{-1}

<em>Simplify:</em>

m = -5

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