As each chair needs 12.6667 feet lumber.So 15 chairs will need 15*12.6667=190.0005 lumber
Answer:
c) 6x - 5y = 15
Step-by-step explanation:
Slope-intercept form of a linear equation: 
(where m is the slope and b is the y-intercept)
Maria's line: 
Therefore, the slope of Maria's line is 
If two lines are perpendicular to each other, the product of their slopes will be -1.
Therefore, the slope of Nate's line (m) is:

Therefore, the linear equation of Nate's line is:

Rearranging this to standard form:



Therefore, <u>option c</u> could be an equation for Nate's line.
Answer:
$300
Explanation:
$10(cost of 1 book) x 5(how many comes in packages) = 50 ( total cost of 1 package)
Mr. Swanson ordered 6 so...
$50 x 6 = $300
Mr. Swanson would have $50 let's over
7x+4=32
7x=28
X=4
Creo que así se ase
Answer:
The solution to the system of equations is:
x = 2, and y = -1
Explanation:
Given the pair of equations:
4x + 5y = 3 ..........................................................................(1)
2x + 3y = 1............................................................................(2)
To solve this by elimination:
Multiply equation (2) by 2, to eliminate x
Equation (2) becomes
4x + 6y = 2 .........................................................................(3)
Subtract equation (1) from (3)
4x - 4x + 6y - 5y = 2 - 3
y = -1 ....................................................................................(4)
Multiply equation (1) by 3 and equation (2) by 5 to eliminate y
Equation (1) becomes
12x + 15y = 9 .......................................................................(5)
Equation (2) becomes
10x + 15y = 5 ........................................................................(6)
Subtract equation (6) from (5)
12x - 10x + 15y - 15y = 9 - 5
2x = 4
Divide both sides by 2
x = 4/2 = 2 ............................................................................(7)
From equations (7) and (4)
x = 2, and y = -1