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3 years ago

X + y = 4 3x + 4y= 14

Mathematics

2 answers:

Vaselesa [24]3 years ago

7 0

Y = 4 - x
3x + 4(4-x) = 14
3x + 16 -4x = 14
-x = -2
x = 2
y = 2

kupik [55]3 years ago

5 0

Answer:

$x = 2$

$y = 2$

Step-by-step explanation:

$x + y = 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ...1\\ 3x + 4y= 14 \: \: \: \: \: \: \: \: \: \: \: ...2\\ \\$

from equation 1 we get

$x = 4 - y$

put x = 4 - y in equation 2

$3(4 - y) + 4y= 14 \\ 12 - 3y + 4y = 14 \\ y = 14 - 12 \\ y = 2$

again, put y = 2 in equation 1

$x + 2 = 4 \\ x = 4 - 2 \\ x = 2$

thus, x = 2 and y = 2

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Example :
u have an endpoint at (6,5)......ad the midpoint is (4,2)....find the other endpoint.

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
one endpoint (6,5)....x1 = 6 and y1 = 5
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m = (6 + x) / 2, (5 + y) / 2

okay, so the midpoint is (4,2)....so ur x value will equal 4
(6 + x) / 2 = 4...multiply both sides by 2
6 + x = 4 * 2
6 + x = 8
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x = 2 <==

midpoint is (4,2)....so the y value will equal 2
(5 + y) / 2 = 2 ...multiply both sides by 2
5 + y = 2 * 2
5 + y = 4
y = 4 - 5
y = -1 <==

so ur other endpoints are (2,-1)

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3 years ago

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3 years ago

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Pavel [41]

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3 years ago

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If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?

Diano4ka-milaya [45]

Answer:

$x=8$

$\m\angle HFG= 80^\circ$

Step-by-step explanation:

Given that:

Point $H$ is interior of $\angle EFG$ .

$m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ$

To find:

$x = ?\\m\angle HFG = ?$

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

$m\angle EFG = m\angle EFH + m\angle HFG$

Putting all the values given in above equation, we get:

$(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}$

$m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}$

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3 years ago

Please help The dilation DO,2.5 is applied to triangle ABC below. Use the dilation of triangle ABC and its image to prove that t

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$\frac{y-5}{x-(-5)} = \frac{-2.5-5}{2.5-(-5)} \\ \\ \frac{y-5}{x+5} = \frac{-7.5}{2.5+5} = \frac{-7.5}{7.5} =-1 \\ \\ \Rightarrow y-5=-(x+5)=-x-5 \\ \\ \Rightarrow y=-x$

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3 years ago

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