Answer:
0.167m/s
Explanation:
According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.
Given momentum = Maas × velocity.
Momentum of glider A = 1kg×1m/s
Momentum of glider = 1kgm/s
Momentum of glider B = 5kg × 0m/s
The initial velocity of glider B is zero since it is at rest.
Momentum of glider B = 0kgm/s
Momentum of the bodies after collision = (mA+mB)v where;
mA and mB are the masses of the gliders
v is their common velocity after collision.
Momentum = (1+5)v
Momentum after collision = 6v
According to the law of conservation of momentum;
1kgm/s + 0kgm/s = 6v
1 =6v
V =1/6m/s
Their speed after collision will be 0.167m/s
Answer:
The male gamete is smaller in comparison to that of the female gamete.
The male gamete is conical from the front while the female gamete is spherical.
The cytoplasm in the male gamete is less in comparison to that of the female gamete.
The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.
The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.
The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.
Explanation:
Joseph's experiment could be improved by using the same antenna at each part of the house during each trial instead of using different antenna. By doing so, he can obtain accurate results how is the signal in different part of the house under the same conditions (despite the location). So, he will see the dependence of the signal on the location. If he uses different antenna, than this antenna can also have influence of the signal.
the answer to your question would be D.
