Answer:
F' = 169.45N
This is a vector addition involving two vectors. In order to do this correctly, we need to resolve each of those forces into their vertical and horizon components and sum them up accordingly (all vertical components summed together and all horizontal components summed together). Then the magnitude of the summation is found by taking the square root of the sun of the squares of the summations along the vertical and the horizontal.
Explanation:
See the attachment below for the full solution to the problem.
Thank you for reading this post. I hope it is helpful to you.
3. It is not changing at that time
Explanation:
If the acceleration of a body is zero at some instant in time, it implies that the velocity is not changing at that point in time. Velocity is the rate of change of displacement with time.
✓Acceleration and velocity shares a very close relationship.
✓ For a body to accelerate, the velocity must change. Acceleration is defined as the rate of change of velocity with time.
✓If at any point, a body moves with constant velocity i.e the velocity does not change with time, the acceleration becomes zero.
✓ For acceleration to occur, a body must change velocity.
Learn more:
Acceleration brainly.com/question/6323625
#learnwithBrainly
Given parameters:
Acceleration of the car = 1.6m/s
Initial speed = 80km/hr
Final speed = 110km/hr
Solution:
Time taken to achieve this speed = ?
Solution:
Acceleration is the rate of change of velocity with the time taken.
Mathematically;
a = 
where a is the acceleration
V is the final velocity
U is the initial velocity
T is the time taken
Now make the unknown time the subject of the expression;
aT = V - U
T = 
Convert the given acceleration to km/hr;
1.6m/s = 1.6 x 
x 
x 
= 5.76km/hr
Input the parameters and solve;
T = 
= 5.2hrs
The time taken is 5.2hrs
I have done this assignment before so I can tell you the more length that hangs over the table, the less vibration there is due to lack of tension.
Answer:
120 m
Explanation:
Given:
wavelength 'λ' = 2.4m
pulse width 'τ'= 100T ('T' is the time of one oscillation)
The below inequality express the range of distances to an object that radar can detect
τc/2 < x < Tc/2 ---->eq(1)
Where, τc/2 is the shortest distance
First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'
f = c/λ (c= speed of light i.e 3 x 
m/s)
f= 3 x / 2.4
f=1.25 x hz.
As, T= 1/f
time of one oscillation T= 1/1.25 x
T= 8 x 
s
It was given that pulse width 'τ'= 100T
τ= 100 x 8 x => 800 x s
From eq(1), we can conclude that the shortest distance to an object that this radar can detect:
= τc/2 => (800 x x 3 x )/2
=120m
