All are true except the first two.
Answer:
9064.44 Nm
Explanation:
Since the steel is uniform, the center of mass is also at the geometric center, which is 3.5 / 2 = 1.75 m from the bolted point.
Let g = 9.81 m/s2. The weight of the beam and the worker is


So the total torque about the bolted point is the sum of product of weights and distances from weight to the bolted point

Newton's second law of motion:
F=ma

You convert from km/h to m/s by dividing by 3.6:


Then a is:


Then:
F=(980)(2.8)=2744 N