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2 years ago

Identify the wavelength of this wave.

Physics

1 answer:

Zolol [24]2 years ago

3 0

Answer:

Explanation:

The line(A) goes throughout the entire picture. So therefore choice A would be it's length.

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Which equation is used to calculate the electric potential in an electric field from a point charge?

scZoUnD [109]

Answer:

The electric potential (voltage) $V$ produced by a point charge $Q$ , at any point in space, is given by the following equation:

$V=k\frac{Q}{r}$

Where:

$k=8.99(10)^{9} Nm^{2}/C^{2}$ is the Coulomb's constant

$r$ is the distance

The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.

6 0

3 years ago

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s

Veseljchak [2.6K]

Answer:

$v_{avg} = 0$

Explanation:

The object is moving to and fro about its mean position

and the equation for its displacement is given as

$s = 5 sin(\pi t) + 5 cos(\pi t)$

now in one complete time period we know that the the object will complete its one oscillation

So the change in the position of the object in one complete time period will be ZERO

so here we can say that

$v_{avg} = \frac{displacement}{time}$

since change in position is zero

so displacement = 0

$v_{avg} = 0$

4 0

3 years ago

When plate tectonics cause cracks to form, _____________.

egoroff_w [7]

I think its probably
B. Volcanoes can occur.

7 0

2 years ago

Read 2 more answers

1. A huge spool of wire, 10,000 meters long, weighs 81.34 N. You cut off a meter or so and tie it between two posts, 0.660 m apa

WARRIOR [948]

Answer:

The beat frequency is 6.378 Hz.

Explanation:

Given that,

Length of wire = 10000 m

Weight = 81.34 N

Distance = 0.660 m

Tension = 52 N

Frequency = 196 Hz

We need to calculate the mass of the wire

Using formula of weight

$W= mg$

$m = \dfrac{W}{g}$

Put the value into the formula

$m=\dfrac{81.34}{9.8}$

$m=8.3\ kg$

The mass per unit length of the wire

$m_{l}=\dfrac{m}{l}$

Put the value into the formula

$m_{l}=\dfrac{8.3}{10000}$

$m_{l}=8.3\times10^{-4}\ kg/m$

We need to calculate the frequency in the wire

Using formula of frequency

$f_{w}=\dfrac{1}{2l}\sqrt{\dfrac{T}{m_{l}}}$

Put the value into the formula

$f_{w}=\dfrac{1}{2\times0.660 }\sqrt{\dfrac{52}{8.3\times10^{-4}}}$

$f_{w}=189.62\ Hz$

We need to calculate the beat frequency

Using formula of beat frequency

$f_{b}=f_{in}-f_{w}$

Put the value into the formula

$f_{b}=196-189.622$

$f_{b}=6.378\ Hz$

Hence, The beat frequency is 6.378 Hz.

5 0

2 years ago

17) The charge of an anti-charm quark isapproximately equal to

Gnom [1K]

The charge of an anti-charm quark is approximately equal to +5.33 ×10⁻²⁰ C.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

The charge on electron is equal to e = -1.6 x 10⁻¹⁹C

The charge of an anti- charm quark is +23 times the magnitude of charge on electron.

So, charge on anti- charm quark is

q = +1/3 x ( 1.6 x 10⁻¹⁹C)

q = +5.33 ×10⁻²⁰ C

Thus, the charge of an anti-charm quark is approximately equal to +5.33 ×10⁻²⁰ C.

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

7 0

2 years ago