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Dmitrij [34]
3 years ago
9

What happens when sunlight is passed through a prism?

Physics
2 answers:
Alenkinab [10]3 years ago
7 0
When light passes through a prism<span> the </span>light<span> bends. As a result, the different colors that make up white </span>light<span> become separated. This </span>happens<span> because each color has a particular wavelength and each wavelength bends at a different angle.</span>
finlep [7]3 years ago
7 0

Answer:

answer is visible light splits to form the electromagnetic I hope it will help you please follow me

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Explanation:

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Which of the following describes the products of a chemical reaction? A. The original materials B. The substances that are chang
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The products of a chemical reaction are the substances that are changed and the chemicals on the right side of a chemical equation. The correct options are B and C.

<h3>What is chemical reaction?</h3>

The chemical reaction  is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

The reactants lie on the left side and products lie on the right side of the reaction.

Thus, the correct options are B and C.

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2 years ago
The name of C (S) + o2 (g) CO2 (g)
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carbon + oxygen → carbon dioxide

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Read 2 more answers
a wire of a certain material has resistance r and diameter d a second wire of the same material and length is found to have resi
777dan777 [17]

Answer:

<h2>d₂ = 3d</h2><h2>The diameter of the second wire is 3 times that of the initial wire.</h2>

Explanation:

Using the formula for calculating the resistivity of an object to find the diameter.

Resistivity P = RA/L

R is the resistance of the material

A is the cross sectional area

L is the length of the material

Since A = πd²/4

P = R( πd²/4)/L

P = Rπd²/4L ... 1

If the second wire of the same material and length is found to have resistance R/9, the resistivity of the second material will be;

P₂ = (R/9)A₂/L₂

P₂ = (R/9)(πd₂²/4)/L₂

P₂ = (Rπd₂²/36)/L₂

P₂ = (Rπd₂²)/36L₂

Since the length and resistivity are the same;

P = P₂  and L =L₂

Equating 1 and 2;

Rπd²/4L =  (Rπd₂²)/36L₂

Rπd²/4L =  (Rπd₂²)/36L

d² = d₂²/9

d₂² = 9d²

Taking the square root of both sides;

√d₂² = √9d²

d₂ = 3d

Therefore the diameter of the second wire is 3 times that of the initial wire

5 0
3 years ago
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