The best logical answer is A
Answer:
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Explanation:
For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as
q = (2h³/3μ) (ΔP/L)
h = hydraulic depth = 4mm/2 = 2mm = 0.002 m
μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s
(ΔP/L) = 26 KPa/m = 26000 Pa/m
q = (2h³/3μ) (ΔP/L)
q = (26000) × (2(0.002³)/(3×0.38))
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Answer: 7.3seconds
Explanation:
Using the echo concept, before echo can occur, we must have an object making the sound (the teacher), the diatance between the object and the reflector (x)(i.e the wall), the time taken for the shadow to disappear (t) and the velocity of sound /movement of the object (v). Using the relationship 2x = vt
According to the question, x = 12m (initial distance), v = speed of object t = time of disappearance.
We have time before disappearance calculated as 2 × 12/1.1 = 21.8s
When he is 4m from the building, it will there take 4 × 21.8/12 = 7.3seconds for his shadow to decrease on the way.
Explanation:
Given that,
Mass of the block, m = 5 kg
Spring constant, k = 2000 N/m
The block is pulled down 5.0 cm from the equilibrium position and given an initial velocity of 1.0 m/s back towards equilibrium.
(a) The angular frequency is given by :
Since, , f is frequency
(b) The velocity of particle executing SHM is given by :
x is displacement from equilibrium position
(c) The total mechanical energy of the motion in SHM is given by :
Hence, this is the required solution.