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Nina [5.8K]
3 years ago
5

Which best describes how energy transferred from an electron in the solar wind compares with energy absorbed by an electron in t

he oxygen atom?
equal to

less than

No energy is transferred.

greater than
Physics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

equal to

(sorry if this is late)

Explanation:

Rest of the answers.

As solar wind approaches Earth, what happens to the charged electrons?

They are deflected as Earth’s magnetic field exerts force on them.

Which best describes how energy transferred from an electron in the solar wind compares with energy absorbed by an electron in the oxygen atom?

equal to

Which statement is accurate about how the aurora borealis is formed?

When the electrons fall to a lower energy state, they release energy as electromagnetic radiation, light.

How does the energy in the light of the aurora borealis compare to the energy as an excited electron returns to its original energy level?

equal to

During the formation of the aurora borealis, the electrons in an atom experience a change in energy levels. Which statement about this change is accurate?

First, the electron absorbs energy to move to a higher energy level.

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<span>τf = p F
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3 years ago
A grandfather clock is controlled by a swinging brass pendulum that is 1.2 m long at a temperature of 27°C. (a) What is the leng
stealth61 [152]

Answer:

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

Explanation:

Given;

Initial length L1 = 1.2m

Initial temperature T1 = 27°C

Final temperature T2 = 0.0°C

Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C

The change i length ∆L;

∆L = L2 - L1

L2 = L1 + ∆L ...........1

∆L = xL1(∆T)

∆L = xL1(T2 - T1) ......2

Substituting the given values into equation 2;

∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)

∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)

∆L = -6.156 × 10^-4 m

From equation 1;

L2 = L1 + ∆L

Substituting the values;

L2 = 1.2 m + (- 6.156 × 10^-4 m)

L2 = 1.2 m - 6.156 × 10^-4 m

L2 = 1.1993844 m

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

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