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agasfer [191]
2 years ago
10

An objest with the mass of 2 kg is accelerated at 4 m/s2. the net force acting on the object is

Physics
1 answer:
poizon [28]2 years ago
5 0
From Newton’s 2nd law of motion
F=ma
= 2*4
=8N

8N should be the answer
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What two factors affect the strength of a magnetic field
Stels [109]

Answer:

Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core.

Explanation:

I HOPE I HELPED :)

7 0
3 years ago
A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
Hoochie [10]

The acceleration of the box is approximately 1 m/s^2

Explanation:

According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:

\sum F = ma

where

\sum F is the net force

m = 12.0 kg is the mass of the box

a is the acceleration

The net force can be written as

\sum F = F_a - F_f

where

F_a = 20 N is the applied forward force

F_f=9.0 N is the friction force

Combining the two equations,

F_a-F_f=ma

And solving for the acceleration,

a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

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8 0
3 years ago
How does the force of friction change when the normal force changes?
77julia77 [94]
The friction force is given by:

F_f= \mu F_N

Where μ is the coefficient of friction (static or kinetic) and F_N is the normal force.  So we say the friction force is directly proportional to the normal force with a constant of proportionality equal to the coefficient of friction.
8 0
2 years ago
A ball has an electric charge of +1.5 × 10-9 coulombs. At what distance from the ball's center is the electric field strength eq
dimaraw [331]
E=Fe/q                                                      
5.8x10^5N/C=Fe/(1.5x10^-9C)             
Fe=(5.8x10^5N/C)(1.5x10^-9C)
Fe=8.7x10^-4N

Fe=kq1q2/r²
8.7X10^-4N=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/r²
r²=(8.99x10^9N·m²/C²)(1.5x10^-9C)(1.5x10-9C)/(8.7x10^-4N)
√r²=√0.00002325
The final answer is r=4.8x10-3m

5 0
3 years ago
Read 2 more answers
I got it wrong, someone tell me the answer
Elodia [21]

Answer:

Explanation:

6

3 0
2 years ago
Read 2 more answers
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