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Papessa [141]
3 years ago
5

Tracie measured 87.47 mg of cholesterol in 0.03 mL of blood. What is the density of this mixture in g/mL?

Chemistry
1 answer:
Lelu [443]3 years ago
5 0

We can use a simple equation to solve this problem.


d = m/v


Where d is the density, m is the mass and v is the volume.


d = ?

m = 87.47 mg = 87.47 x 10⁻³ g

v = 0.03 mL


By applying the equation,

  d = 87.47 x 10⁻³ g / 0.03 mL

  d = 2.92 g/mL



Hence, the density of the mixture is 2.92 g/mL.


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What is the change in internal energy ( ΔU ) of the system if q = –8 kJ and w = –1 kJ for a certain process?
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Change in internal energy (ΔU) = -9 KJ

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Octane has a density of 0.692 g/ml at 20∘c. how many grams of o2 are required to burn 17.0 gal of c8h18
german

156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈

<h3>Further explanation</h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}

ρ = density

m = mass

v = volume

1 gal equal to = 3785.41 ml

then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane

grams Octane = ρ x ml

grams Octane = 0.692 g.ml x 64351.97

grams Octane = 44531.563

molar mass Octane (C₈H₁₈) = 114

mole Octane = grams : molar mass

mole Octane = 44531.563  : 114

mole Octane = 390.627

From the reaction

C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O

mole C₈H₁₈ : mole O₂ = 1 : 25/2

mole\:O_2\:=\:\frac{25}{2} \times\:390.627

mole O₂ = 4882.846

grams O₂ = mole x molar mass

grams O₂ = 4882.846 x 32

grams O₂ = 156251.099

<h3>Learn more </h3>

moles of water

brainly.com/question/1405182

grams of oxygen required

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mass of copper required

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Keywords: Octane,  mole, mass, gal, density

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