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Oksana_A [137]
3 years ago
8

The braking effect of the engine is greatest when the engine is _____ the governed rpm and the transmission is in the ______ gea

rs.
Physics
1 answer:
Arisa [49]3 years ago
3 0

When the engine is near the governed RPMand the transmission is in the lower gears, the braking effect of the engine is at its greatest .


It is specified that the legal requirements for the braking system that:

A reasonable distance should be practiced in stopping your vehicle.


Adjournment from the jar or shudder should be smooth and free.


A good braking system’s other necessities are:

Unaffected by heat, water, road grit, dust etc.

Constant continued application while moving downwards from a hill should not decrease its effectiveness and it must have good anti fade characteristics


Adequate durability with economical maintenance and adjustment Its durability must be enough and must have proper adjustment and maintenance. 

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Alinara [238K]
<span>The value of the constant needed to complete in joules to three significant figures is 2.18 x 10^-18 J.</span>
6 0
4 years ago
A 1.0 kg mass is attached to the end of a vertical ideal spring with a force constant of 400 N/m. The mass is set in simple harm
Marina86 [1]

Answer:

v(0)=2m/s

Explanation:

The instantaneous velocity of a point mass that executes a simple harmonic movement is given by:

v(t)=\omega  *A*cos(\omega t + \phi)

Where:

\omega=Angular\hspace{3}frequency\\A=Amplitude\\\phi=Initial\hspace{3}phase

Express the amplitude in meters:

10cm*\frac{1m}{100cm} =0.1m

The angular frequency can be found using the next equation:

\omega=\sqrt{\frac{k}{m} }

Using the data provided:

\omega=\sqrt{\frac{400}{1} } =20

At the equilibrium position:

\phi=0

v(0)=20*(0.1)cos(20*0+0)=2*cos(0)=2*1=2m/s

6 0
4 years ago
A particle of charge q moving through a magnetic field B experiences the force where v is the velocity of the particle. Show tha
MrRa [10]

Answer:

       dx/Dt x B . x  =0

Explanation:

Let's calculate the work and the magnetic force, the expression for magnetic force is

        F = qv x B

Bold indicate vector quantities, the expression for the job is

         W = F. X

Let's replace in this equation

       W = q v x B . X

The definition of speed is

      v =  dX / dt

With what work is left

     W = q dX / dt x B . X

As we can see the vector product gives us a vector perpendicular to dX and its scalar product by X of zero

Second part

   The speed a vector and although the magnitude is constant the change of direction implies a change in the speed.

   Let's calculate the magnitudes of speed (speed)

       F = qv B sin θ

       F = ma

       q v B sin θ = ma

       a = qvB / m senT

     

This acceleration is perpendicular to the magnetic field and the velocity, so it does not change if magnitude but its direction, it is directed to the center of the circle.

   | v | = q vB/m sin θ

3 0
4 years ago
It takes brooke 10minutes to run 1 mile what is her speed in miles per minutes
hjlf

If you divide miles by minutes, the answer will have units of
miles per minute, which is exactly what you want.

(1 mile) / (10 minutes) = 1/10  mile/minute = 0.1 mile per minute


6 0
4 years ago
A sled is accelerating down a hill at a rate of 1 m s2 . If the mass of the sled is suddenly cut in half and the net force on th
mihalych1998 [28]
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
4 0
3 years ago
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