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3 years ago

9

Which is always true in a closed system?

1 answer:

Tanya [424]3 years ago

4 0

Answer:

The correct option is momentum is conserved

Explanation:

A closed system is a system that is independent/free of external factors/force and does not exchange matter with its surrounding. Since a close system is free of external factors/force; <em>acceleration is constant in it, mass is conserved in it and there will be changes in velocities of objects in the closed system</em>.

This question actually seeks to test our knowledge of the law of momentum. The law of conservation of momentum states that the momentum of a closed system is conserved.

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ASAP!!! A cell phone charger supplies 2.0A of current to your phone. you plug in your phone overnight (8 hours). how much charge

Ksivusya [100]

current = charges / times (sec)

if a current of 2A flows for 8 hours(28800sec), then 2 * 28800 = 57600 coulombs of electrical charge move through the phone

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4 years ago

A boat has a mass of 31,999 kg and a plane has a mass of 110,000 kg. What is the ratio of weight of the plane to the boat?

Gelneren [198K]

Answer:

3.44:1

Explanation:

We use ratios to find the ratio of weight.

Mass of Plane= 110000 kg ∴ W= mg

Mass of Boat =31999 kg

$\frac{weight of plane}{weight of boat}$ = $\frac{110000*9.81}{31999*9.81}$

= $\frac{3.44}{1}$

SO 3.44:1

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4 years ago

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stiv31 [10]

The answer is Car 1 and Car 2.

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4 years ago

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A 0.5 kg block is attached to a spring (k = 12.5 N/m). The damped frequency is 0.2% lower than the natural frequency, (a) What i

Tju [1.3M]

Answer:

a) 1.58 kg s^{-1}

b) x_m e^{-1.58t} x_m is initial amplitude

c) 5 kg s^{-1}

Explanation:

given data:

mass =0.5 kg

k = 12.5 N/m

from the data given

a) $w_d = w_o - \frac{0.2}{100}w_o$

$= w_o - 0.002w_o = 0.99w_o$

$w_d = \sqrt{\frac{k}{m} - \frac{b^2}{4m^2}$

$0.998w_o = \sqrt{w_o^2 - \frac{b^2}{4m^2}$

$(0.998w_o)^2 = w_o^2 -\frac{b^2}{1}$

$b^2 = w_o^2 -(0.998w_o)^2$

$b^2 = w_o^2(1-0.998^2) = 3.996 *10^{-3} w_o^2$

$b = w_o\sqrt{3.996*10^{-3}}$

$b = \frac{12.5}{0.5}\sqrt{3.996*10^{-3}} = 1.58 kg s^{-1}$

b) $x = x_m e^{\frac{-bt}{2m}}$

$x = x_m e^{-1.58t}{1} = x_m e^{-1.58t}$ where x_m is initial amplitude

c) critical damping amplitude

$c_c =2\sqrt{km} = 2\sqrt{12.5*.5} = 5 kg s^{-1}$

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3 years ago

Find the de Broglie wavelength of an electron whose speed is 1.0 x 10^7 m/s.

balu736 [363]

Answer:

7*10^(-11) m.

Explanation:

the details are in the attached picture (the answer is marked with red).

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4 years ago