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Vedmedyk [2.9K]
3 years ago
12

A 75 kg doctor delivers a 4 kg baby and holds it at arm's length (0.3 m). Using the Universal Law of Gravitation formula below,

identify F, G, m1, m2, r. *
Physics
1 answer:
stepan [7]3 years ago
3 0

Answer:

m₁ = 75 kg

m₂ = 4 kg

r = 0.3 m

G = 6.67 x 10⁻¹¹ Nm²/kg²

F = 2.223 x 10⁻⁷ N

Explanation:

Given;

mass of the doctor, m₁ = 75 kg

mass of the baby, m₂ = 4 kg

length of the doctor's arm, r = 0.3 m

universal gravitation constant, G = 6.67 x 10⁻¹¹ Nm²/kg²

The gravitational force F, is calculated as;

F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67*10^{-11})(75 \ kg) (4 \ kg)}{(0.3 \ m)^2} \\\\F = 2.223 *10^{-7} \ N

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