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Akimi4 [234]
3 years ago
15

The lower the ph of a solution, the ______.

Chemistry
2 answers:
Alinara [238K]3 years ago
6 0

Answer: b.more acidic the solution

Explanation:

pH is the measure of acidity or alkalinity of a solution.  Acids are substances which gives H^+ ions when dissolved in water.

HX\rightarrow H^++X^-

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=log\frac {1}{H^+}

Thus as pH and H^+ are inversely related, a solution having lower pH will have more amount of H^+ concentration , a lower amount of OH^_ concentration and will be more acidic.

gtnhenbr [62]3 years ago
3 0
B

a and c are unrelated
d: ph will increase
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If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

Learn more about pH here:

brainly.com/question/24595796

#SPJ1

 

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