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miss Akunina [59]
3 years ago
5

How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *

Chemistry
1 answer:
serg [7]3 years ago
6 0

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

Fraction remaining (FR) = 0.5n

n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

-1.81 = -0.301 n

n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

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By stoichiometry,

1 mole of Zinc metal produces 1 mole of Hydrogen gas, therefore

\text{5 moles of Zinc metal will produce}=\frac{1}{1}\times 5=5\text{ moles of Hydrogen gas}

Amount of Hydrogen gas produced can be calculated by:

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Why is it important to balance the redox equation for the electrolysis of water?.
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Oxidation and reduction processes occur simultaneously and never in isolation, which is why they are called redox reactions.

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