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miss Akunina [59]
2 years ago
5

How many half-lives will pass by the time 1.56% of I-131 is present? B. Approximately how many days does that equal? *

Chemistry
1 answer:
serg [7]2 years ago
6 0

Answer: Hmmmmm that's crazy....

There are a couple of equations one could use for this type of problem, but I find the following to be the easiest to use and to understand.

Fraction remaining (FR) = 0.5n

n = number of half lives that have elapsed

In this problem, we need to find n and are given the FR, which is 1.56% or 0.0156 (as a fraction).

0.0156 = 0.5n

log 0.0156 = n log 0.5

-1.81 = -0.301 n

n = 6.0 half lives have elapsed

Explanation:

Just wanted to help. Hopefully it's correct wouldn't want to waster your time ;)

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Potassium hypochlorite when dissolved in water would dissociate into ions namely the potassium ions and the hypochlorite ions. Furthermore, hypochlorite ions would interact with water molecules and would decompose further. The dissociation reactions are as follows:

KClO <=> K+ + ClO-
ClO- + H2O <=> HOCl + OH-

Adding the two reactions, would give

KClO + ClO- + H2O = K+ + HOCl + OH- + ClO- 

The two ClO- ions in both sides would cancel giving us the net ionic equation:

KClO + H2O = K+ + HOCl + OH-
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You go to the same school as me BAHAHHAHA
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