1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sphinxa [80]
2 years ago
7

How does an enzyme’s active site relate to its substrate?

Chemistry
2 answers:
Fofino [41]2 years ago
7 0

Answer:

The enzyme's active site must be the mold shape of the substrate.

Explanation:

An enzyme and a substrate bind together in order to work. If the shapes of the 2 are different, they will not be able to bond together. If the shapes of the 2 fit glove-in-hand, then they will be able to bond together.

Nataly [62]2 years ago
4 0

Answer:

Hope this helps you =D

Explanation:

An enzymes active site attaches to its substrate. When they both bind together they make a complex enzyme. This means that different enzymes can’t attach to other active sites they only match up with the one that has the same pattern.

You might be interested in
If you had a sample containing 55 alpha particles, how many protons would be present in that sample? Show all necessary work.
arlik [135]
An alpha particle is a helium nucleus without the electrons - 2 neutrons and 2 protons.

So, all you would have to do is 2 x 55, which equals 110.

8 0
3 years ago
Which will have the MOST kinetic energy?
Alenkasestr [34]

Answer:

should be B

because the player has more mass than the puck

Explanation:

7 0
2 years ago
4P+ 5O2 -> P4O10
Ratling [72]
If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2

so .611 moles

so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams

so first ans is .611 moles and second is 34.7 grams !

if you have any problem regarding this , just comment !!!
4 0
3 years ago
Read 2 more answers
How are the hydrogen atom and lithium atom similar?
Juli2301 [7.4K]
They both have 1 electron in their valence shell.....
5 0
2 years ago
Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2
ArbitrLikvidat [17]
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)

Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol

Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol

<em>Answer: -1367.5 kJ/mol</em>
6 0
3 years ago
Read 2 more answers
Other questions:
  • 1. Is this equation balanced? Explain your answer. Na + Cl2 → NaCl ?
    10·2 answers
  • Molecular shape of XeOF4​​
    8·1 answer
  • The molecular mass of octane is 114.22 g/mol. What is the mass of 22.05 mol of octane? 5.180 g 22.05 g 114.22 g 2,518 g
    13·2 answers
  • How do I find the number of atoms in grams of an element?
    9·1 answer
  • The energy needed to create bonds between two hydrogen molecules is measured in units called __________
    8·1 answer
  • You just measured a metal cylinder and obtained the following information: mass - 3.543 g diameter -0.53 cm height = 4.40 cm. 26
    8·1 answer
  • What is the correct description of lactic acid fermentation
    9·1 answer
  • The temperature of a sample of gas in a steel tank at 0.30 ATM at 25 Celsius if the pressure W20.59 ATM what would be the final
    9·1 answer
  • A piece of silver wire has a mass of 53.91 grams. How many moles of<br> silver are in the wire?
    5·1 answer
  • (HELP ASAP) what is the reaction for Si + S₈ --&gt; Si₂S₄
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!