As,
CuCO₃ ⇆ Cu²⁺ + CO₃²⁻
So,
Kc = [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
Kc (CuCO₃) = [Cu²⁺] [CO₃²⁻]
Or,
Ksp = [Cu²⁺] [CO₃²⁻]
As,
Ksp = 1.4 × 10⁻¹⁰
So,
1.4 × 10⁻¹⁰ = [x] [x]
Or,
x² = 1.4 × 10⁻¹⁰
Or,
x = 1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
x = 1.18 × 10⁻⁵ mol/L × 123.526 g/mol
x = 1.45 × 10⁻³ g/L
The hydrogens and oxygen of a water molecule are held together by covalent bonds.
<h3>
What are covalent bonds?</h3>
A covalent bond is an electron exchange that causes the production of electron pairs between atoms. Covalent bonding is a stable equilibrium of the attractive and repulsive forces between two atoms that occurs when they share electrons.
Bonding pairs or sharing pairs are other names for these electron pairs. Because electrons are shared among several molecules, each atom can reach the equivalent of a full valence shell, resulting in a stable electronic state.
In organic chemistry, covalent bonds are much more common than ionic bonds. Covalent bonds unite the atoms in a single water molecule, whereas hydrogen bonds join two water molecules. Water develops a covalent bond when oxygen shares an electron with each hydrogen atom.
To know more about covalent bonds, refer:
brainly.com/question/3447218
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Answer: 90 grams
0.5 molar of glucose means 0.5mole glucose for 1 liter of water. Since we want to made 1L of solution, then the amount of glucose needed is: 0.5mole/l x 1l= = 0.5mole
Glucose molecular weight is 180, then 0,5 mol of glucose is= 0.5mole x 180 grams/mole= 90 grams.
Answer and Explanation:
a) The direction is shown in the cube diagram attached to this solution.
b) the angle between two planes (h₁, k₁, l₁) and (h₂, k₂, l₂) is given by the formula,
Cos Φ = (h₁h₂ + k₁k₂ + l₁)/√((h₁² + k₁² + l₁²)(h₂² + k₂² + l₂²))
For (111) and (112)
Cos Φ = (1.1 + 1.1 + 1.2)/√((1² + 1² + 1²)(1² + 1² + 2²))
Cos Φ = (1 + 1 + 2)/√((1+1+1)(1+1+4))
Cos Φ = 4/√(3×6)
Cos Φ = 4/√18
Φ = cos⁻¹ (4/√18) = 19.56°
c) equation 3.3 is missing from the question, I would be back to provide the answers to that as soon as the equation is provided!
Hope this Helps!!
