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Sphinxa [80]
3 years ago
7

How does an enzyme’s active site relate to its substrate?

Chemistry
2 answers:
Fofino [41]3 years ago
7 0

Answer:

The enzyme's active site must be the mold shape of the substrate.

Explanation:

An enzyme and a substrate bind together in order to work. If the shapes of the 2 are different, they will not be able to bond together. If the shapes of the 2 fit glove-in-hand, then they will be able to bond together.

Nataly [62]3 years ago
4 0

Answer:

Hope this helps you =D

Explanation:

An enzymes active site attaches to its substrate. When they both bind together they make a complex enzyme. This means that different enzymes can’t attach to other active sites they only match up with the one that has the same pattern.

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An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 eV, 27 eV, and 48 eV. What
Fynjy0 [20]

Answer:

l=3.5*10^{-10}m

Explanation:

From the question we are told that:

1st Energy     E_1=12eV=4(3eV)

2nd Energy  E_2=27eV=9(3eV)

3rd Energy   E_3=48eV=16(3eV)

 

Generally the equation for Energy E for electron in one dimensional box at ground state E_0 is mathematically given by

  E_0=\frac{h}{8ml^2}

  E_0=\frac{h}{8ml^2}

Therefore Length a is mathematically given as

l=\sqrt{\frac{h^2}{8mE_0} }

l=\sqrt{\frac{(6.625*10^{-34})^2}{8(9.1*19^{-31}{(3eV(1.6*10^{-19}))}}

l=3.5*10^{-10}m

8 0
3 years ago
Some plants can grow from both blank and blank
LUCKY_DIMON [66]
Plants can grow from sunlight and water.
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3 years ago
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Which of these solutes raises the boiling point of water the most?
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I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
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What the Purpose of seeds
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3 years ago
Determine the empirical formula of a compound containing 1.71 g of silicon and 8.63 g of chlorine.
Basile [38]

Answer:

The answer to your question is: SiCl₄

Explanation:

Data

amount of Si      1.71 g

amount of Cl     8.63 g

MW Si = 28 g

MW Cl = 35.5

Process (rule of three)

For Si                                                        For Cl

        28 g of Si ------------------ 1 mol                      35.5 g of Cl --------------- 1 mol

          1.71g of Si  ---------------   x                              8.63 g of Cl --------------  x

         x = 1.71 x 1 / 28 = 0.06 mol                          x = 8.63 x 1 / 35.5 = 0.24 mol

Now, divide both results by the lowest of them.

Si = 0.06 mol / 0.06 = 1 molecule of Si     Cl = 0.24 / 0.06 = 4 molecules of Cl

Finally

                     Si₁ Cl₄ or SiCl₄

8 0
3 years ago
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