Question

When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 10.085 g at 20ºC. If the density of water is taken to be 0.9975 g/mL at 20ºC, what is the percent error for the 10 mL of water.

Answer 1

The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value  * 100
The || is needed to get the absolute value of the difference. Substituting the values,

Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/0.9975 g/mL  * 100
Percent error = 1.1%