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Minchanka [31]
3 years ago
7

How many formula units make up 12.8 g of magnesium chloride (MgCl2)? Express the number of formula units numerically.

Chemistry
1 answer:
Cloud [144]3 years ago
6 0
<h3>Answer:</h3>

8.09 × 10²² formula units

<h3>Explanation:</h3>

Mass of MgCl₂ is 12.8 g

Required to calculate the formula units

1 mole of a compound contains the Avogadro's number formula units

That is;

1 mole = 6.022 × 10²³ formula units

<h3>Step 1: Calculate the moles of MgCl₂ in 12.8 g </h3>

The molar mass of MgCl₂ is 95.211 g/mol

Number of moles = Mass ÷ molar mass

Moles of MgCl₂ = 12.8 g ÷ 95.211 g/mol

                          = 0.1344 mole

<h3>Step 2: Calculate the formula units of MgCl₂</h3>

1 mole =  6.022 × 10²³ formula units

Therefore;

Number of formula units = Moles × 6.022 × 10²³ formula units

                                    = 0.1344 mole × 6.022 × 10²³ formula units

                                     = 8.09 × 10²² formula units

Therefore, there are 8.09 × 10²² formula units in 12.8 g of MgCl₂

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<span>9.40x10^19 molecules.
   The balanced equation for ammonia is:
 N2 + 3H2 ==> 2NH3
   So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
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   Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
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   Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
   Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol

Now to convert from moles to molecules, just multiply by Avogadro's number: 1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
   Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
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