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nadya68 [22]
3 years ago
15

Find an equation of the line. Write the equation using function notation.

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

y = -4x+9

Step-by-step explanation:

Given equation of line is:

4y=x-8

We have to convert the given line in slope-intercept form to find the slope of the line

So,

Dividing both sides by 4

\frac{4y}{4} =\frac{x-8}{4}\\y = \frac{1}{4}x-\frac{8}{4}\\y = \frac{1}{4}x-2

Let m1 be the slope of given line

Then

m_1 = \frac{1}{4}\\

Let m2 be the slope of line perpendicular to given line

As we know that produt of slopes of two perpendicular lines is -1

m_1.m_2 = -1\\\frac{1}{4} . m_2 = -1\\m_2 = -1*4\\m_2 = -4

The slope intercept form of line is given by:

y = m_2x+b

Putting the value of slope

y = -4x+b

to find the value of b, putting (3,-3) in equation

-3 = (-4)(3) + b\\-3 = -12 +b\\b = -3+12\\b = 9

Putting the value of b in the equation

y = -4x+9

Hence,

The equation of line perpendicular to 4y = x-8 passing through (3,-3) is:

y = -4x+9

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/4837736
  • brainly.com/question/4805611

#LearnwithBrainly

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Answer:

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So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Solution to the problem

The confidence interval for the mean is given by the following formula:

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The margin of error is given by:

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Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

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