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MaRussiya [10]
3 years ago
15

Help asap I will give brainleast

Physics
1 answer:
NARA [144]3 years ago
5 0
3rd option. Plant D and E did not have enough radiant energy
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neptune is an average distance of 4.5×10^12m from the sun. Estimate the length of the Neptunian year.
Vikentia [17]

As per Kepler's third law we know that

\frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3}

now here we know that

T_1 = year of Neptune

T_2 = year of Earth

R_1 = distance of Neptune from Sun

R_2 = Distance of Earth from Sun

so now we will have

\frac{T_1^2}{1} = \frac{(4.5 \times 10^{12})^3}{(1.5 \times 10^11)^3}

T_1^2 = 27000

T_1 = 164.3 years

so length of year of Neptune is 164.3 years

6 0
3 years ago
How are light years used to measure distances in the universe
FinnZ [79.3K]
A light year is a unit of distance. It is a distance that light can travel in a years time which is six trillion miles. It is used to measure the distances in space. To take one example, the distance to the next nearest big galaxy, the Andromeda Galaxy, from earth is 21,000,000,000,000,000,000 km. 
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4 0
3 years ago
Uploaded imageTwo long, parallel wires each carry the same current I in the same direction (see figure below). The total magneti
LekaFEV [45]

Answer:

Zero

Explanation:

Two long parallel wires each carry the same current I in the same direction. The magnetic field in wire 1 is given by :

B_1=\dfrac{\mu_oI_1}{2\pi r}

Magnetic force acting in wire 2 due to 1 is given by :

F_{2}=I_2lB_1

F_2=\dfrac{\mu_oI_1I_2 l}{2\pi r}

Similarly, force acting in wire 1 is given by :

F_1=\dfrac{\mu_oI_1I_2 l}{2\pi r}According to third law of motion, the force acting in wire 1 will be in opposite direction to wire 2 as :

F_2=-F_1

So, the total magnetic field at the point P midway between the wires is in what direction will be zero as the the direction of forces are in opposite direction.  

7 0
3 years ago
A seesaw pivots as shown in below. What is the net torque about the pivot point?
rodikova [14]

Answer:

2.3 Nm clockwise

Explanation:

Take counterclockwise to be positive and clockwise to be negative.

∑τ = (3 N) (2.5 m) − (7 N) (1.4 m)

∑τ = 7.5 Nm − 9.8 Nm

∑τ = -2.3 Nm

The net torque is 2.3 Nm clockwise.

7 0
4 years ago
A space probe is launched from Earth headed for deep space. At a distance of 10,000 miles from Earth's center, the gravitational
Pavlova-9 [17]
<span> gravitational force varies based on 1/r^2
when you're double the distance =10,000 to 20,000, the force is 4 times smaller so on and so forth.
</span><span>As force is proportional to 1 / {distance squared}, the force will be 1 / 2^2 (i.e. 1/4) of the force at the reference distance (i.e. 1/4 * 600 = 150 lb)
</span>hope this helps
5 0
4 years ago
Read 2 more answers
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