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3 years ago

Help asap I will give brainleast

Physics

1 answer:

NARA [144]3 years ago

5 0

3rd option. Plant D and E did not have enough radiant energy

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I need help solving this

Alja [10]

Answer: let me think

Explanation:

3 0

3 years ago

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the product of the pressure and the volume

11111nata11111 [884]

I’m stuck on this too

4 0

3 years ago

For an extended object, the weight force can be considered to act at which point?

JulsSmile [24]

Answer:

At the center of the object

At the end of the object farthest away from the ground

At the center of gravity of the object

At end of the object closest to the ground

Explanation:

5 0

3 years ago

The energy released during a nuclear reaction is a result of

astra-53 [7]

Answer:

the conversion of matter into energy

Explanation:

A nuclear reaction is a reaction in which there is a change in the nuclei of the atoms involved. The two most important examples of nuclear reactions are:

- Nuclear fission: it occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei

- Nuclear fusion: it occurs when two lighter nuclei fuse together into a heavier nucleus

In both cases, the total mass of the final products is smaller than the total mass of the initial nuclei: this means that part of the mass of the initial nuclei has been converted into energy, according to Einstein's formula:

$E=\Delta m c^2$

where $\Delta m$ is the variation of mass and c is the speed of light. Since the value of c is very large, we can see from the formula that even a small amount of $\Delta m$ is able to produce a huge amount of energy, and this is a typical feature of any nuclear reaction.

8 0

3 years ago

Determine the magnitude of the resultant force acting on a 5 −kg particle at the instant t=2 s, if the particle is moving along

Alex787 [66]

Answer:

F = 296.7N

Explanation:

The x and y component of the position vector are given by:

$x(t) =rcos\phi, y(t) = rsin\phi\\ \frac{dx}{dt} =\frac{dr}{dt} cos\phi - rsin\phi\frac{d\phi}{dt} , \frac{dy}{dt}=\frac{dr}{dt}sin\phi + rcos\phi\frac{d\phi}{dt}\\ \frac{d^2x}{dt^2} = \frac{d^2r}{dt^2} cos\phi - \frac{dr}{dt} sin\phi\frac{d\phi}{dt} -\frac{dr}{dt} sin\phi\frac{d\phi}{dt} - r(cos\phi\frac{d^2\phi}{dt^2} + sin\phi\frac{d^2\phi}{dt^2})$

$\frac{d^2y}{dt^2} = \frac{d^2r}{dt^2} sin\phi + \frac{dr}{dt} cos\phi\frac{d\phi}{dt}+\frac{dr}{dt}cos\phi\frac{d\phi}{dt}+r(-sin\phi\frac{d^2\phi}{dt^2} +cos\phi\frac{d^2\phi}{dt^2})$

At t = 2s:

$\phi(2) = 1.5t^2-6t= -6\\ \frac{d\phi}{dt}(2) = 3t-6=0\\ \frac{d^2\phi}{dt^2}=3\\r(2)=2t+10=14\\ \frac{dr}{dt}=2\\\frac{d^2r}{dt^2} = 0$

Plugging in:

$\frac{d^2x}{dt^2}=-42(cos(-6) + sin(-6))=-52\frac{m}{s^2} \\\frac{d^2y}{dt^2} = 42(cos(-6)-sin(-6))=28.6\frac{m}{s^2}$

The resulting force F is:

$F = m\sqrt{(\frac{d^2x}{dt^2})^2 + (\frac{d^2y}{dt^2})^2}=296.7N$

5 0

3 years ago