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Reika [66]
3 years ago
10

What are Base Quantities ?​

Physics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

<em>physical quantities that cannot be defined in terms of other quantities.</em>

<em>Examples</em><em>:</em><em> </em><em>Length - meter (m)Time - second (s)Amount of substance - mole (mole)Electric current - ampere (A)Temperature - kelvin (K)Luminous intensity - candela (cd)Mass - kilogram (kg)</em>

tatyana61 [14]3 years ago
3 0

Answer:

Base quantities are physical quantities that cannot be defined in terms of other quantities

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What will occur when the trough of wave A overlaps the trough of wave B?
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Constructive interference will occur, which means the waves will combine.

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3 0
3 years ago
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You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
Fed [463]

Answer:

9.81 × 10⁻¹⁰ C

Explanation:

Given:

Distance between the tissue and the tip of the scale, r = 6 cm = 0.06 m

Charge on the ruler, Q = - 12 μC = - 12 × 10⁻⁶ C

Mass of the tissue = 3 g = 0.003 Kg

Now,

The force required to pick the tissue, F = mg

where, g is the acceleration due to gravity

also,

The force between (F) the charges is given as:

F=\frac{kQq}{r^2}

where,

q is the charge on the tissue

k is the Coulomb's constant = 9 × 10⁹ Nm²/C²

thus,

mg=\frac{kQq}{r^2}

on substituting the respective values, we get

0.003\times9.81=\frac{9\times10^9\times(-12\times10^{-6})\times q}{0.06^2}

or

q = 9.81 × 10⁻¹⁰ C

Minimum charge required to pick the tissue paper is 9.81 × 10⁻¹⁰ C

3 0
3 years ago
Block 2 of mass 1.00 kg is at rest on a frictionless surface and touching the end of an unstretched spring of spring constant 20
son4ous [18]

Answer:

x = 0.327 m

Explanation:

Block 2 of mass 1.00 kg is at rest

spring constant = 200 N/m            

Block 1 of mass 2 kg moving at 4 m/s

m₁ v₁ = (m₁ + m₂)V                                

2 x 4 = (2 + 1) V                                                      

V = 2.67 m/s                                                        

loss of kinetic energy = gain elastic potential energy

\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2                  

\dfrac{1}{2}\times (3)\times 2.67^2 = \dfrac{1}{2}\times 200 \times x^2

x = 0.327 m

hence, the spring compressed distance is equal to x = 0.327 m

8 0
3 years ago
In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes were sliding toward each other and cra
san4es73 [151]

Answer:

Box 1 has more mass than box 2.

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3 0
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If you plot the distance d as an ordinate (y-axis) versus the time of fall t as an abscissa (x-axis), do you expect to get a str
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3 0
3 years ago
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