4.8 km because if u add the other bonus if speed and multiply you check the 48 taking off a decimal point
Answer:
Δω = -5.4 rad/s
αav = -3.6 rad/s²
Explanation:
<u>Given</u>:
Initial angular velocity = ωi = 2.70 rad/s
Final angular velocity = ωf = -2.70 rad/s (negative sign is
due to the movement in opposite direction)
Change in time period = Δt = 1.50 s
<u>Required</u>:
Change in angular velocity = Δω = ?
Average angular acceleration = αav = ?
<u>Solution</u>:
<u>Angular velocity (Δω):</u>
Δω = ωf - ωi
Δω = -2.70 - 2.70
Δω = -5.4 rad/s.
<u> Average angular acceleration (αav):</u>
αav = Δω/Δt
αav = -5.4/1.50
αav = -3.6 rad/s²
Since, the angular velocity is decreasing from 2.70 rad/s (in counter clockwise direction) to rest and then to -2.70 rad/s (in clockwise direction) so, the change in angular velocity is negative.
Answer:
both are correct .... ....
Answer:
Em₀ = 245 J
Explanation:
We can solve this problem with the concepts of energy conservation, we assume that there is no friction with the air.
Initial energy the highest point
Em₀ = U
Em₀ = m g h
The height can be found with trigonometry
The length of the pendulum is L and the length for the angle of 60 ° is L ’, therefore the height from the lowest point is
h = L - L’
cos θ = L ’/ L
L ’= L cos θ
h = L (1 - cos θ)
We replace
Em₀ = m g L (1- cos θ)
Let's calculate
Em₀ = 10 9.8 5.0 (1 - cos 60)
Em₀ = 245 J
Answer:
3.53×10⁶ N/c due west
Explanation:
From the question
E = F'/q........................ Equation 1
Where E = Electric Field, F = Net Force, q = Charge.
But,
F' = F₂-F₁...................... Equation 2
Substitute equation 2 into equation 1
E = (F₂-F₁)/q................ Equation 3
Given: F₁ = 3 N due east, F₂ = 15 N due west, q = 3.4×10⁻⁶ C
Substitute these values into equation 1
E = (15-3)/(3.4×10⁻⁶)
E = 12/(3.4×10⁻⁶)
E = 3.53×10⁶ N/c due west
