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3 years ago

If the thrower takes 0.90 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

1 answer:

8 0

Ω₀ = the initial angular velocity (from rest)
t = 0.9 s, time for a revolution
θ = 2π rad, the angular distance traveled

Let
α = the angular acceleration
ω = the final angular velocity

The angular rotation obeys the equation
(1/2)*(α rad/s²)*(0.9 s)² = (2π rad)
α = 15.514 rad/s²

The final angular velocity is
ω = (15.514 rad/s²)*(0.9 s) = 13.963 rad/s

If the thrower's arm is r meters long, the tangential velocity of release will be
v = 13.963r m/s

Answer: 13.963 rad/s

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Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m. What is the

zzz [600]

The magnetic field midway between the two wires is $5.0*10^{-7} T$ .

It is given that Two long parallel wires carry currents of 20 A and 5.0 A in opposite directions. The wires are separated by 0.20 m.

We need to determine the magnetic field midway between the two wires.

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

Magnetic field is a place in space near a magnet or an electric current where a physical field is created from a moving electric charge that creates force on another moving electric charge.

B=B1+B2

= $\frac{4\pi *10^{-7}*20 }{2\pi R1} +\frac{4\pi *10^{-7}*5 }{2\pi R2}$

= $\frac{4\pi *10^{-7}*20 }{2\pi *0.10} +\frac{4\pi *10^{-7}*5 }{2\pi *0.10}$

= $5.0*10^{-7} T$

Hence, the magnetic field midway between the two wires is $5.0*10^{-7} T$

Learn more about magnetic field click here, brainly.com/question/14848188

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2 years ago

A displacement vector with a magnitude of 20. meters could have perpendicular components with magnitudes of A. 10. m and 10. m B

mylen [45]

Answer:10.m and 10. M

Explanation:

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3 years ago

Two small, identical conducting spheres repel each other with a force of 0.030 N when they are 0.65 m apart. After a conducting

solong [7]

Note that the methods applied in solving this question is the appropriate method. Check the parameters you gave in the question if you did not expect a complex number for the charges. Thanks

Answer:

$q_1 = 0.00000119 + j0.00000145 C \\q_2 = 0.00000119 - j0.00000145 C$

Explanation:

Note: When a conducting wire was connected between the spheres, the same charge will flow through the two spheres.

The two charges were 0.65 m apart. i.e. d = 0.65 m

Force, F = 0.030 N

The force or repulsion between the two charges can be calculated using the formula:

$F = \frac{kq^2}{d^2} \\\\0.030 = \frac{9 * 10^9 * q^2}{0.65^2}\\\\q = 1.19 * 10^{-6} C$

Due to the wire connected between the two spheres, $q_1 = q_2 = 1.19 * 10^{-6} C$

The sum of the charges on the two spheres = $q_1 + q_2 = 2.38 * 10^{-6} C$

Note: When the conducting wire is removed, the two spheres will no longer contain similar charges but will rather share the total charge unequally

Let charge in the first sphere = $q_1$

Charge in the second sphere, q₂ = $2.38 * 10^{-6} - q_1$

Force, F = 0.075 N

$F = \frac{k q_1 q_2}{r^2} \\\\0.075 = \frac{9*10^9 * q_1 * (2.38*10^{-6} -q_1 )}{0.65^2}\\\\3.52 * 10^{-12} = q_1 * (2.38*10^{-6} -q_1 )\\\\3.52 * 10^{-12} = 2.38*10^{-6} q_1 - q_1^2\\\\q_1^2 - (2.38*10^{-6}) q_1 + (3.52 * 10^{-12}) = 0\\$

$q_1 = 0.00000119 + j0.00000145 C \\q_2 = 0.00000119 - j0.00000145 C$

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4 years ago

17- How much work is needed for a climber in order to climb 45 m height, where his weight is 70 kg. also, calculate the power re

Snezhnost [94]

Answer:

Work Done= 3150J

Power= 1.75W

Explanation:

Work Done= Force x the distance travelled in the direction of the force (W= f x d)

Weight is a force, i think the qn. stated it wrongly, it should be 70N not 70kg.

Work Done= 70 x 45

=3150J

Power= Work Done/Time

=3150/(30x60)

*convert minutes to seconds since the S.I. unit of Power is joules/seconds(J/s) or watts(W)

=1.75W

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3 years ago

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7nadin3 [17]

Im pretty sure its b........

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3 years ago