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Lapatulllka [165]
4 years ago
12

A woman exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant sp

eed "vo".
1. The constant horizontal force applied by the woman:
a. has the same magnitude as the weight of the box
b. is greater than the weight of the box
c. has the same magnitude as the total force which resists themotion of the box
d. is greater than the total force which resists the motion ofthe box
e. is greater than either the weight of the box or the totalforce which resists its motion
Physics
1 answer:
d1i1m1o1n [39]4 years ago
6 0

Answer:C

Explanation:

When a constant horizontal force is applied to the box, box started moving in the horizontal direction such that it moves with constant velocity v_0

Constant velocity implies that net force on the box is zero

i.e. there must be an opposing force which is equal to the applied force and friction force can serve that purpose.

So option c is the correct choice.      

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Two equal point charges QQQ are separated by a distance ddd. One of the charges is released and moves away from the other due on
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Answer:

The kinetic energy K of the moving charge is K = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

Explanation:

The potential energy due to two charges q₁ and q₂ at a distance d from each other is given by U = kq₁q₂/r.

Now, for the two charges q₁ = q₂ = Q separated by a distance d, the initial potential energy is U₁ = kQ²/d. The initial kinetic energy of the system K₁ = 0 since there is no motion of the charges initially. When the moving charge is at a distance of r = 3d, the potential energy of the system is U₂ = kQ²/3d and the kinetic energy is K₂.

From the law of conservation of energy, U₁ + K₁ = U₂ + K₂

So, kQ²/d + 0 = kQ²/3d + K

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4 0
4 years ago
What what is the change in internal energy if 500 joule of heat is added to a system and 125 joule of work are done on a system
eduard

Answer:

DU = 375 Joules

Explanation:

Given the following data;

Quantity of heat = 500 Joules

Work done = 125 Joules

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

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  • Q is the quantity of energy.
  • W is the work done.

Substituting into the formula, we have;

DU = 500 - 125

<em>DU = 375 Joules</em>

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