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Lapatulllka [165]
3 years ago
12

A woman exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant sp

eed "vo".
1. The constant horizontal force applied by the woman:
a. has the same magnitude as the weight of the box
b. is greater than the weight of the box
c. has the same magnitude as the total force which resists themotion of the box
d. is greater than the total force which resists the motion ofthe box
e. is greater than either the weight of the box or the totalforce which resists its motion
Physics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:C

Explanation:

When a constant horizontal force is applied to the box, box started moving in the horizontal direction such that it moves with constant velocity v_0

Constant velocity implies that net force on the box is zero

i.e. there must be an opposing force which is equal to the applied force and friction force can serve that purpose.

So option c is the correct choice.      

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A water line with an internal radius of 5.29 x 10-3 m is connected to a shower head that has 15 holes. The speed of the water in
fiasKO [112]

Answer:

(a) 3.44 x 10^-3 m^3/s

(b) 8.4 m/s

Explanation:

area of water line, A = 5.29 x 10^-3 m

number of holes, N = 15

Speed of water in line, V = 0.651 m/s

(a) Volume flow rate is given by

V = area of water line x speed of water in water line

V = 5.29 x 10^-3 x 0.651 = 3.44 x 10^-3 m^3/s

(b) area of one hole, a = 4.13 x 10^-4 m

Let v be the velocity of water in each hole

According to the equation of continuity

A x V = a x v

5.29 x 10^-3 x 0.651 = 4.1 x 10^-4 x v

v = 8.4 m/s  

5 0
3 years ago
Radioactive plutonium−239 (t1/2 = 2.44 × 105 yr) is used in nuclear reactors and atomic bombs. If there are 3.50 × 102 g of the
madam [21]

Answer:

t = 4.41 10⁻⁴ years

Explanation:

For this exercise we must use the concept of average life time, which is the time in which the quantity and substance decays in half

    T_{1/2}  = ln2 / λ

Let's calculate the decay constant of plutonium

    λ  = ln2 /  T_{1/2}

    λ  = ln 2 / 2.44 10⁵  

    λ  = 2.84 10⁻⁶  s⁻¹

Radioactive decay is a first order process

     N = No e (-λ   t)

Where N is the number of nuclei, the mass is this by molecular weight

    m = N PM

    m / PM = m₀ / PM e (- λ  t)

    m / m₀ = e (- λ  t)

    -λ  t = ln (m / m₀)

     t = -1 /λ   ln (m/m₀)

     t = - 1 / 2.84 10⁻⁶   ln (0.1 / 0.35)

     t = 4.41 10⁻⁴ years

7 0
3 years ago
Why doesnt the moon get pulled into the sun
VLD [36.1K]

Answer:

The moon does not get pulled into the sun because of gravitational pull.

Explanation:

Gravitational pull is a force that pulls things down or into i guess you can say. Like are orbit, all of the planets (even the dwarf planet "pluto") are circling around are sun but we have things called moons that circle are planets. Are moon is orbiting us like we (are earth) are orbiting the sun. So to get into a little more detail, i will add that we circle the sun or the moon circles us because the action of earth pulling away from the suns gravitational pull is causing it to either rotate or revolve.So we are stuck in the gravitational force of the sun and the moon is stuck in ares. But as someone who LOVES astronamy will say that i watched a video about are earth, sun, and moon and it said that each year are moon is slowly pulling away from the earth. sooner or later we might not have a solar or lunar eclipse anymore.

7 0
3 years ago
Read 2 more answers
3 ways pollution gets into neighborhoods
SashulF [63]

Answer:

1. Leaving trash on the ground and not picking it up.

2. Polluting the lake, if your neighborhood has one.

3. Outside people come and dump their waste to your neighborhood.

Hope this helps!

7 0
3 years ago
A 2010 kg space station orbits Earth at an altitude of 5.35×105 m. Find the magnitude of the force with which the space station
Shkiper50 [21]

Answer:

Force, F = 16814.95 N

Explanation:

It is given that,

Mass of space station, m = 2010 kg

Altitude, d=5.35\times 10^5\ m

Mass of earth, m=5.98\times 10^{24} kg

Mean radius of earth, r=6.37\times 10^6\ m

Magnitude of force is given by :

F=G\dfrac{Mm}{R^2}

R = r + d

R=6.37\times 10^6\ m+5.35\times 10^5\ m=6905000\ m

F=6.67\times 10^{-11}\times \dfrac{2010\ kg\times 5.98\times 10^{24} kg}{(6905000\ m)^2}

F = 16814.95 N

So, the force between the space station and the Earth is 16814.95 N. Hence, this is the required solution.

8 0
3 years ago
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