<h2>Basic Research - Option B</h2>
Experimenting to determine the fundamental properties of x-rays would be an example of basic research. The experimental primary analysis tries to determine the laws of the events. The primary analysis is expected to know the stuff, its sort, its characteristics and its performance. It examines to get the speculation. To obtain wherewith the stuff performance yet not how to practice these forms for a firm determination.
The research of the characteristics of the particle to explain whatever it is, how it combines with other atoms, how it determines the characteristics of the material are some instances of primary analysis. For example examining to ascertain the basic features of x-rays. Spencer's research on WWII radar technology that drove to the discovery of the microwave furnace.
Edison's research and application of other scientists task is to create the light bulb, and Morrison and Franscioni's research was made to build the Frisbee models of applied research science.
Aluminium is ordinarily classified as a metal. It is lustrous, malleable and ductile, and has high electrical and thermal conductivity. Like most metals, it has a close-packed crystalline structure<span> and forms a cation in aqueous solution.</span>
Answer:
Bubbles paused
Explanation:
the air bubble doesn't rise because it is no lighter than the water around it—there's no buoyancy. The droplet doesn't fall from the leaf because there's no force to pull it off. It's stuck there by molecular adhesion.
for instance, onto the International Space Station, gravity becomes negligible, and the laws of physics act differently than here on Earth
On Earth, the buoyancy of the air bubbles causes them to rise to the top together, creating a segregation between air and water. However, in microgravity, nothing forces the air bubbles to interact and thus rise together, Green said.
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.
So
<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)
<em>v</em>² = 4645 m²/s²
<em>v</em> ≈ 68.15 m/s
Answer:
when an object has more velocity, it tends to have less potential energy and more kinetic energy.
Explanation:
kinetic energy is the energy of movment and velocity helps to describe movement
