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Jobisdone [24]
3 years ago
11

Help plz will mark brainliest xD

Chemistry
2 answers:
Paladinen [302]3 years ago
8 0

Answer:

Ions are atoms that have either gain or lose electrons from the neutral atom.

A loss of electrons results in a positive ion, called a cation, a gain of electron results in a negative ion called an anion.

Ionic compounds are formed by the combination of a cation and anion, or metal + nonmetal.

When naming ionic compounds, name the cation first, and the anion second, changing the ending to ide.

Explanation:

Hope it helped!

atroni [7]3 years ago
8 0

Answer:

• [ <u>lost</u> ] or [ <u>gained</u> ]

• [ <u>cation</u> ], [ <u>anion</u> ]

• [ <u>metal</u> ] + [ non-metal ]

• [ <u>cation</u> ] and the [ <u>anion</u> ] to [ <u>compound</u><u> </u><u>with</u><u> </u><u>suffix</u><u> </u><u>"</u><u>ide</u><u>"</u><u> </u><u>or</u><u> </u><u>"</u><u>ode</u><u>"</u> ]

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An element has two naturally occurring isotopes, X-85 with a mass of 84.9118 amu and a natural abundance of 72.17%, and X-87 wit
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Answer:

This element is Rubidium (Rb) and has an average atomic mass of 85.468 u

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The average mass of an element is calculated by taking the average of the atomic masses of its stable isotopes.

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Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

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In the <u>second reaction</u>, one compound is getting split into two new compounds and is a decomposition reaction.

In the <u>third reaction</u>,  \rm Br^{-} in \rm 2NaBr and \rm (OH)_{2} in \rm Ca(OH)_{2} are anions and cations and exchanges their places to produce two new compounds  \rm CaBr_{2} + 2NaOH.

In the <u>fourth reaction</u>, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, \rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH is the double displacement reaction.

Learn more about double displacement reaction here:

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