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finlep [7]
2 years ago
6

Vishwanath had some money. he spent 3 upon 4 part of money to buy goods for his birthday,1 upon 5 part of money give to his sist

er and the rest of Rs.40 to mother how much did he have at first ​
Chemistry
1 answer:
lord [1]2 years ago
8 0

Answer:

The correct answer is - 800.

Explanation:

Given:

Total amount = ? or assume x

spend in buying birthday item = 3/4 of x

given to sister = 1/5 of x

remaining to mother = 40

solution:

the remaning amount = x- (3x/4+x/5) = 4=

=> x- 19x/20 = 40

=> x = 20*40

=> x = 800

thus, the correct answer is = 800

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2H₂ + O₂ ⇒ 2H₂O

<h3>Further explanation</h3>

Conservation of mass states that

<em>In a closed system, the masses before and after the reaction are the same</em>

So it can be concluded

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So let's see which of the several options , which one has the same number of atoms on both sides of the equation

2H₂ + O₂ ⇒ 2H₂O

H ⇒ left 4, right 4

O ⇒ left 2, right 2

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Assume the volume of the crew cabin is 74,000 L. The pressure is maintained at around 1.00 atm, ideally with an 80% nitrogen and
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Answer:

The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles

Explanation:

The given parameters are;

Volume of the crew cabin = 74,000 L

Pressure of the crew cabin = 1.00 atm

Percentage of nitrogen in the mixture of gases in the cabin = 80%

Percentage of oxygen in the mixture of gases in the cabin = 20%

Temperature of the cabin = 20°C = 293.15 K

Therefore, volume of oxygen in the crew cabin = 20% of 74,000 L

Hence, volume of oxygen in the crew cabin = \frac{20}{100} \times 74,000 \, L = 14,800 \, L

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Where:

n = Number of moles  of oxygen

P = Pressure = 1.00 atm

V = Volume of oxygen = 14,800 L

T = Temperature = 293.15 K

R = Universal Gas Constant = 0.08205 L·atm/(mol·K)

Plugging in the values, we have;

n = \frac{1 \times 14,800 }{0.08205   \times  293.15 } = 615.309 \, moles

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