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ryzh [129]
4 years ago
8

The weight of an elephant is 100 times the weight of a cat. If the elephant weighs 14,000 pounds, how many pounds does the cat w

eigh? How did you find the answer?​
Mathematics
2 answers:
klasskru [66]4 years ago
4 0

Answer:

14 lb

Step-by-step explanation:

10^3 = 1000

14,000 lb/1000 = 14 lb

Since the weight of the elephant is 1000 times the weight of the cat, then the weight of the cat is one-thousandth of the weight of the elephant. To find one-thousandth of a number, divide the number by 1000. 14,000 lb divided by 1000 is 14 lb.

P.S. I feel much better for the cat.

Illusion [34]4 years ago
4 0
The cat weighs 140 pounds as 14,000 (the elephant) divided by 100 as it is 100 times the amount is 140.
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Alinara [238K]

Answer:

x=12/5

Step-by-step explanation:

4x + 16 - x= 22 + 6

5x+16=28

5x=28-16

5x=12

x=12/5

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A sample of trail mix has 15 peanuts an 10 raisins give the % of raisins in the mix!
joja [24]

Answer:

40%

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25 divided by 5 = 5

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6 0
3 years ago
For each of the following statements about sets A, B, and C, either prove the statement is true or give a counterexample to show
Lina20 [59]

Answer:

a. True

b. False

c. True

d. False

Step-by-step explanation:

a. Meaning

as we can see that x is an element of Y

So notation is

x \in Y

Therefore x is the subset of Y if each of an element of X is also an element of Y.

So notation is

X \subseteq Y

2. (a) We need to proof

When A \subseteq B and B \subseteq C \so A \subseteq C

We will say that A, B and C are the set that is A\subseteq B\ and\ B\subseteq C

When A = ∅ then A\subseteq C which shows true, as the set of empty is a subset of each set.

Hence, it is safe to say that A is not the empty set.

Now we will proof directly

Let us say x be an element of A

x \in A

As A \subseteq B, each of the element of A is also an element of B

x \in B

As B \subseteq C, each if the element of B is also an element of C

x \in C

Therefore, as we can see that each of an element of A is also known an element of C, that states A \subseteq C

So, the given statement is true, as we conclude with a proof.

(b). We will assume {1}, B = {{1},2} and C = {{1},2,3}

As in the point a, which is an element of B, that is A \in B which is true

As all of the elements in B are also an element in C, B \subseteq C which is also correct.

Although, A \subseteq C is false as 1 is an element of A that is not in C.

(c) We need to proof

When  A \in B\ and \ B \subseteq C then A \in C

Let us assume that A, B and C are the sets that A\in B\ and\ B \subseteq C

As, A \in B, \which\ is\ an\ element\ of\ the\ set\ B

A\in B

As, B \subseteq C, each of the element of B is also an element of C

A\in C

So, its true.

(d) We will assume {1}, B = {{1},2} and C = {{1},2,3}

As in the point a, which is an element of B, that is A \in B which is true

As {{1},2} is an element of B, B \in C is correct

Although A \in C is not correct as {1) is not an element in C.

SO the statement is false

5 0
3 years ago
What would be the measure of angle J?
horsena [70]

Answer:

5q I would say

Step-by-step explanation:

As

3

x

−

q

=

5

q

, adding

=

q

on both sides, we get

3

x

−

q

+

q

=

5

q

+

q

or

3

x

=

6

q

, now multiplying both sides by

1

3

, we get

3

x

×

1

3

=

2

6

q

×

1

3

or

x

=

2

q

4 0
3 years ago
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