Given reaction represents dissociation of bromine gas to form bromine atoms
Br2(g) ↔ 2Br(g)
The enthalpy of the above reaction is given as:
ΔH = ∑n(products)Δ
- ∑n(reactants)Δ
where n = number of moles
Δ
= enthalpy of formation
ΔH = [2*ΔH(Br(g)) - ΔH(Br2(g))] = 2*111.9 - 30.9 = 192.9 kJ/mol
Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol
The answer to your question is A I think
Answer:
answer is 34.996 or 35 grams
Explanation:
Br2 + AlCl3
mass 34.996 29.2
RFM 160 133.5
moles 0.2187 0.2187
Which element is a metalloid? <span>B. Silicon (Si)
</span>
Looking at the periodic table, which element is a metal? <span>D. Strontium (Sr)
</span>Argon (Ar) is a noble gas, silicon (Si) is a metalloid, hydrogen (H) is a non-metal, and strontium is a alkaline earth metal.
<span>
I have used the periodic table from </span><span>http://chemreference.com/elements/1/properties?display=periodic&trend=number to help me when I'm unsure.</span>
<span>C3H7
The unknown compound consists of only carbon and hydrogen. The oxygen comes from the air. So you need to first determine the relative moles of hydrogen and carbon that are present in the CO2 and H2O. First, look up the molar masses of Carbon, Hydrogen, and Oxygen. Then determine the molar masses of CO2 and H2O.
Carbon = 12.0107
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of CO2
1 * 12.0107 + 2 * 15.999 = 44.0087
Molar mass of H2O
2 * 1.00794 + 1 * 15.999 = 18.01488
Number of moles of CO2
22.1 g / 44.0087 g/mol = 0.502173
Number of moles of H2O
10.5 g / 18.01488 g/mol = 0.582852
Since there's 1 carbon atom per CO2 molecule, there are 0.502173 moles of carbon.
Since there's 2 hydrogen atoms per H2O molecule, there are 2 * 0.582852 = 1.165703 moles of hydrogen.
Now we need to find a simple ratio of small integers that comes close to the ratio of 0.502173 / 1.165703 = 0.43079 to determine the empirical formula.
3/7 = 0.428571, an error of only 0.002219. The next closest ratio has an error of 0.013654, over 6 times larger.
So the empirical formula is C3H7</span>
