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Vanyuwa [196]
4 years ago
14

On a baseball team, the ages of each of the players are as follows: 21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33;

34; 35; 36; 36; 36; 36; 38; 38; 38; 40 Use your calculator or computer to find the mean and standard deviation. Then find the value that is two standard deviations above the mean.
Mathematics
1 answer:
Paul [167]4 years ago
6 0

Answer:

Mean = 30.68

Standard deviation = 6.095

Two standard deviations above the mean = 42.87

Step-by-step explanation:

Given the following data :

21; 21; 22; 23; 24; 24; 25; 25; 28; 29; 29; 31; 32; 33; 33; 34; 35; 36; 36; 36; 36; 38; 38; 38; 40

Mean = Σ(x) / n

n = 25

Σ (X) = 767

Mean (m) = 767 / 25

Mean (m) = 30.68

Standard deviation : sqrt[Σ(x - m) / n]

Using a calculator :

Standard deviation = 6.095 ( 2 decimal places)

2 standard deviations above the mean :

Mean + 2(standard deviation)

Mean + 2(6.095)

30.68 + 12.19

30.68 + 12.19

= 42.87

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Find the domain of the following expression 15 - √(x+2)
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[-2, ∞]

Step-by-step explanation:

15 - √(x+2)

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3 years ago
If two fractions are between 0 and 1, can their product be more than 1? please explain. Thank You.
notka56 [123]

Answer:

B) always less than either of the original fractions

Step-by-step explanation:

We can easily Answer this by taking some values.

The question states that the two fractions, each have values between 0 and 1.

Let us say one of the fraction is 1/2 and the other fraction is 1/3 .

The product of the two fractions is 1/2 x 1/3 = 1/6 .

is lesser than both 1/2  and 1/3 .

So, the correct answer is that the product is always less than either of the original fractions.

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3 years ago
2y=-3+2<br> Graph the equation
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This is the graph of the equation

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3 years ago
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
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