Are the two expressions equvalent 7(8x+5) and 48x + 35

Which of the following activities is most likely to result in nutrient pollution? a. cutting down trees b. pouring motor oil dow

gtnhenbr [62]

Excess fertilizer use results in nutrient pollution by effecting the nutrition values of the plants we eat.

Cutting down trees more likely to result in air pollution by an increase in greenhouse gases.

Pouring oil in drain creates water pollution which is not a nutrient source.

7 0

4 years ago

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Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that

kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.

Explanation:

The Young's modulus is given by:

$E = \frac{FL_{0}}{A\Delta L}$

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

$A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}$

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

$F = T_{w} = W_{o}$

Where:

$T_{w}$ : is the tension of the wire

$W_{o}$ : is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

$F = mg = 1700 kg*9.81 m/s^{2} = 16677 N$

Hence, the Young's modulus is:

$E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa$

Therefore, Young's modulus for the rope material is 20.8 MPa.

I hope it helps you!

7 0

3 years ago

If an object has a kinetic energy of 30 j and mass of 34kg how fast is the object moving ?

Murrr4er [49]

Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.

Ek = mv^2 / 2 — multiply both sides by 2

2Ek = mv^2 — divide both sides by m

2Ek / m = V^2 — switch sides

V^2 = 2Ek / m — plug in values

V^2 = 2*30J / 34kg

V^2 = 60J/34kg

V^2 = 1.76 m/s — sqrt of both sides

V = sqrt(1.76)

V = 1.32m/s (roughly)

5 0

3 years ago

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include

Ket [755]

Answer:

E = 1.64 x 10⁶ V/m

Explanation:

The electric field in the region between the plates can be given by the following formula:

$E = \frac{\Delta V}{d}$

where,

E = Electric Field = ?

ΔV = Poetential Difference across the plates = 23 KV = 23000 V

d = distance between plates = 1.4 cm = 0.014 m

Therefore, using these values in the equation, we get:

$E = \frac{23000\ V}{0.014\ m}$

5 0

3 years ago

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillation are

givi [52]

Answer :

Explanation :

It is given that,

length of pendulum, l = 0.6 m

Number of oscillation, n = 20

time, t = 35.5 seconds

so, Time period, $T=\dfrac{t}{n}$

$T=\dfrac{35.5s}{20}$

we know that the time period of pendulum is given by

$T=2\pi\sqrt{\dfrac{l}{g}}$

$g=\dfrac{4\pi^2l}{T^2}$

$g=\dfrac{4\times(3.14)^2\times 0.6 \times (20)^2}{(35.5s)^2}$

$g=7.51\ m/s^2$

or

$g=7.52\ m/s^2$

6 0

3 years ago