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monitta
4 years ago
6

What's your normal body temperature? it may not be 98.6°f, the oft-quoted average that was determined in the nineteenth century.

a more recent study has reported an average temperature of 98.2°f. what is the difference between these averages, expressed in celsius degrees?
Physics
3 answers:
harkovskaia [24]4 years ago
6 0

(98.6 - 98.2)ºF = .4ºF

.4ºF* 5ºC/9ºF = 0.222 ºC

Igoryamba4 years ago
6 0

(98.6 - 98.2)ºF = .4ºF

.4ºF* 5ºC/9ºF = 0.222 ºC

givi [52]4 years ago
6 0

(98.6 - 98.2)ºF = .4ºF

.4ºF* 5ºC/9ºF = 0.222 ºC OR

98.6*5ºC/9ºF = 54.80 98.25ºC/9ºF = 54.60 54.80 - 54.60 = .2ºC

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The displacement is the distance and direction from the place
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-- It's distance is the hypotenuse of the right triangle whose legs
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