um ima em forma de barra atravessa uma espira retangular, como mostra a imagem. Sabendo que esse e um caso em que o fluxo magnet
ico sobre a espira esta variando, descreva o que acontecera na espira enquanto o ima se movimenta
1 answer:
Answer:De acuerdo con la ley de inducción electromagnética de Faraday, la tasa de cambio del flujo magnético vinculado con la bobina es directamente proporcional a la fem inducida en la bobina.
e = - d∅ / dt
Entonces, si el cambio de flujo es mayor, la fem inducida es mayor.
¡espero haber ayudado a tener un buen día! :)
Explanation:
According to the Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is directly proportional to the induced emf in the coil.
e = - d∅ / dt
So, if the flux change is more the induced emf is more.
i hope i helped have a good day! :)
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Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.